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Maximum and minimum

From Wikipedia, the free encyclopedia
(Redirected fromGlobal maximum)
Largest and smallest value taken by a function at a given point
"Extreme value" redirects here. For other uses, seeExtreme value (disambiguation).
"Maximum" and "Minimum" redirect here. For other uses, seeMaximum (disambiguation) andMinimum (disambiguation).
Local and global maxima and minima for cos(3πx)/x, 0.1≤ x≤1.1

Inmathematical analysis, themaximum andminimum[a] of afunction are, respectively, the greatest and least value taken by the function. Known generically asextremum,[b] they may be defined either within a givenrange (thelocal orrelative extrema) or on the entiredomain (theglobal orabsolute extrema) of a function.[1][2][3]Pierre de Fermat was one of the first mathematicians to propose a general technique,adequality, for finding the maxima and minima of functions.

As defined inset theory, the maximum and minimum of aset are thegreatest and least elements in the set, respectively. Unboundedinfinite sets, such as the set ofreal numbers, have no minimum or maximum.

Instatistics, the corresponding concept is thesample maximum and minimum.

Definition

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A real-valuedfunctionf defined on adomainX has aglobal (orabsolute)maximum point atx, iff(x) ≥f(x) for allx inX. Similarly, the function has aglobal (orabsolute)minimum point atx, iff(x) ≤f(x) for allx inX. The value of the function at a maximum point is called themaximum value of the function, denotedmax(f(x)){\displaystyle \max(f(x))}, and the value of the function at a minimum point is called theminimum value of the function, (denotedmin(f(x)){\displaystyle \min(f(x))} for clarity). Symbolically, this can be written as follows:

x0X{\displaystyle x_{0}\in X} is a global maximum point of functionf:XR,{\displaystyle f:X\to \mathbb {R} ,} if(xX)f(x0)f(x).{\displaystyle (\forall x\in X)\,f(x_{0})\geq f(x).}

The definition of global minimum point also proceeds similarly.

If the domainX is ametric space, thenf is said to have alocal (orrelative)maximum point at the pointx, if there exists someε > 0 such thatf(x) ≥f(x) for allx inX within distanceε ofx. Similarly, the function has alocal minimum point atx, iff(x) ≤f(x) for allx inX within distanceε ofx. A similar definition can be used whenX is atopological space, since the definition just given can be rephrased in terms of neighbourhoods. Mathematically, the given definition is written as follows:

Let(X,dX){\displaystyle (X,d_{X})} be a metric space and functionf:XR{\displaystyle f:X\to \mathbb {R} }. Thenx0X{\displaystyle x_{0}\in X} is a local maximum point of functionf{\displaystyle f} if(ε>0){\displaystyle (\exists \varepsilon >0)} such that(xX)dX(x,x0)<εf(x0)f(x).{\displaystyle (\forall x\in X)\,d_{X}(x,x_{0})<\varepsilon \implies f(x_{0})\geq f(x).}

The definition of local minimum point can also proceed similarly.

In both the global and local cases, the concept of astrict extremum can be defined. For example,x is astrict global maximum point if for allx inX withxx, we havef(x) >f(x), andx is astrict local maximum point if there exists someε > 0 such that, for allx inX within distanceε ofx withxx, we havef(x) >f(x). Note that a point is a strict global maximum point if and only if it is the unique global maximum point, and similarly for minimum points.

Acontinuous real-valued function with acompact domain always has a maximum point and a minimum point. An important example is a function whose domain is a closed and boundedinterval ofreal numbers (see the graph above).

Search

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Finding global maxima and minima is the goal ofmathematical optimization. If a function is continuous on a closed interval, then by theextreme value theorem, global maxima and minima exist. Furthermore, a global maximum (or minimum) either must be a local maximum (or minimum) in the interior of the domain, or must lie on the boundary of the domain. So a method of finding a global maximum (or minimum) is to look at all the local maxima (or minima) in the interior, and also look at the maxima (or minima) of the points on the boundary, and take the greatest (or least) one.

Fordifferentiable functions,Fermat's theorem states that local extrema in the interior of a domain must occur atcritical points (or points where the derivative equals zero).[4] However, not all critical points are extrema. One can often distinguish whether a critical point is a local maximum, a local minimum, or neither by using thefirst derivative test,second derivative test, orhigher-order derivative test, given sufficient differentiability.[5]

For any function that is definedpiecewise, one finds a maximum (or minimum) by finding the maximum (or minimum) of each piece separately, and then seeing which one is greatest (or least).

Examples

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The global maximum ofxx occurs atx =e.
FunctionMaxima and minima
x2Unique global minimum atx = 0.
x3No global minima or maxima. Although the first derivative (3x2) is 0 atx = 0, this is aninflection point. (2nd derivative is 0 at that point.)
xx{\displaystyle {\sqrt[{x}]{x}}}Unique global maximum atx =e. (See figure at right)
xxUnique global maximum over the positive real numbers atx = 1/e.
x3/3 −xFirst derivativex2 − 1 andsecond derivative 2x. Setting the first derivative to 0 and solving forx givesstationary points at −1 and +1. From the sign of the second derivative, we can see that −1 is a local maximum and +1 is a local minimum. This function has no global maximum or minimum.
|x|Global minimum atx = 0 that cannot be found by taking derivatives, because the derivative does not exist atx = 0.
cos(x)Infinitely many global maxima at 0, ±2π, ±4π, ..., and infinitely many global minima at ±π, ±3π, ±5π, ....
2 cos(x) −xInfinitely many local maxima and minima, but no global maximum or minimum.
cos(3πx)/x with0.1 ≤x ≤ 1.1Global maximum atx = 0.1 (a boundary), a global minimum nearx = 0.3, a local maximum nearx = 0.6, and a local minimum nearx = 1.0. (See figure at top of page.)
x3 + 3x2 − 2x + 1 defined over the closed interval (segment) [−4,2]Local maximum atx = −1−15/3, local minimum atx = −1+15/3, global maximum atx = 2 and global minimum atx = −4.

For a practical example,[6] assume a situation where someone has200{\displaystyle 200} feet of fencing and is trying to maximize the square footage of a rectangular enclosure, wherex{\displaystyle x} is the length,y{\displaystyle y} is the width, andxy{\displaystyle xy} is the area:

2x+2y=200{\displaystyle 2x+2y=200}
2y=2002x{\displaystyle 2y=200-2x}
2y2=2002x2{\displaystyle {\frac {2y}{2}}={\frac {200-2x}{2}}}
y=100x{\displaystyle y=100-x}
xy=x(100x){\displaystyle xy=x(100-x)}

The derivative with respect tox{\displaystyle x} is:

ddxxy=ddxx(100x)=ddx(100xx2)=1002x{\displaystyle {\begin{aligned}{\frac {d}{dx}}xy&={\frac {d}{dx}}x(100-x)\\&={\frac {d}{dx}}\left(100x-x^{2}\right)\\&=100-2x\end{aligned}}}

Setting this equal to0{\displaystyle 0}

0=1002x{\displaystyle 0=100-2x}
2x=100{\displaystyle 2x=100}
x=50{\displaystyle x=50}

reveals thatx=50{\displaystyle x=50} is our onlycritical point.Now retrieve theendpoints by determining the interval to whichx{\displaystyle x} is restricted. Since width is positive, thenx>0{\displaystyle x>0}, and sincex=100y{\displaystyle x=100-y}, that implies thatx<100{\displaystyle x<100}.Plug in critical point50{\displaystyle 50}, as well as endpoints0{\displaystyle 0} and100{\displaystyle 100}, intoxy=x(100x){\displaystyle xy=x(100-x)}, and the results are2500,0,{\displaystyle 2500,0,} and0{\displaystyle 0} respectively.

Therefore, the greatest area attainable with a rectangle of200{\displaystyle 200} feet of fencing is50×50=2500{\displaystyle 50\times 50=2500}.[6]

Functions of more than one variable

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Main article:Second partial derivative test
Peano surface, a counterexample to some criteria of local maxima of the 19th century
The global maximum is the point at the top
Counterexample: The red dot shows a local minimum that is not a global minimum

For functions of more than one variable, similar conditions apply. For example, in the (enlargeable) figure on the right, the necessary conditions for alocal maximum are similar to those of a function with only one variable. The firstpartial derivatives as toz (the variable to be maximized) are zero at the maximum (the glowing dot on top in the figure). The second partial derivatives are negative. These are only necessary, not sufficient, conditions for a local maximum, because of the possibility of asaddle point. For use of these conditions to solve for a maximum, the functionz must also bedifferentiable throughout. Thesecond partial derivative test can help classify the point as a relative maximum or relative minimum.In contrast, there are substantial differences between functions of one variable and functions of more than one variable in the identification of global extrema. For example, if a bounded differentiable functionf defined on a closed interval in the real line has a single critical point, which is a local minimum, then it is also a global minimum (use theintermediate value theorem andRolle's theorem to prove this bycontradiction). In two and more dimensions, this argument fails. This is illustrated by the function

f(x,y)=x2+y2(1x)3,x,yR,{\displaystyle f(x,y)=x^{2}+y^{2}(1-x)^{3},\qquad x,y\in \mathbb {R} ,}

whose only critical point is at (0,0), which is a local minimum withf(0,0) = 0. However, it cannot be a global one, becausef(2,3) = −5.

Maxima or minima of a functional

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If the domain of a function for which an extremum is to be found consists itself of functions (i.e. if an extremum is to be found of afunctional), then the extremum is found using thecalculus of variations.

In relation to sets

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Maxima and minima can also be defined for sets. In general, if anordered setS has agreatest elementm, thenm is amaximal element of the set, also denoted asmax(S){\displaystyle \max(S)}. Furthermore, ifS is a subset of an ordered setT andm is the greatest element ofS with (respect to order induced byT), thenm is aleast upper bound ofS inT. Similar results hold forleast element,minimal element andgreatest lower bound. The maximum and minimum function for sets are used indatabases, and can be computed rapidly, since the maximum (or minimum) of a set can be computed from the maxima of a partition; formally, they are self-decomposable aggregation functions.

In the case of a generalpartial order, aleast element (i.e., one that is less than all others) should not be confused with theminimal element (nothing is lesser). Likewise, agreatest element of apartially ordered set (poset) is anupper bound of the set which is contained within the set, whereas themaximal elementm of a posetA is an element ofA such that ifmb (for anyb inA), thenm =b. Any least element or greatest element of a poset is unique, but a poset can have several minimal or maximal elements. If a poset has more than one maximal element, then these elements will not be mutually comparable.

In atotally ordered set, orchain, all elements are mutually comparable, so such a set can have at most one minimal element and at most one maximal element. Then, due to mutual comparability, the minimal element will also be the least element, and the maximal element will also be the greatest element. Thus in a totally ordered set, we can simply use the termsminimum andmaximum.

If a chain is finite, then it will always have a maximum and a minimum. If a chain is infinite, then it need not have a maximum or a minimum. For example, the set ofnatural numbers has no maximum, though it has a minimum. If an infinite chainS is bounded, then theclosureCl(S) of the set occasionally has a minimum and a maximum, in which case they are called thegreatest lower bound and theleast upper bound of the setS, respectively.

Argument of the maximum

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This section is an excerpt fromArg max.[edit]
As an example, both unnormalised and normalisedsinc functions above haveargmax{\displaystyle \operatorname {argmax} } of {0} because both attain their global maximum value of 1 atx = 0.

The unnormalised sinc function (red) hasarg min of {−4.49, 4.49}, approximately, because it has 2 global minimum values of approximately −0.217 atx = ±4.49. However, the normalised sinc function (blue) hasarg min of {−1.43, 1.43}, approximately, because their global minima occur atx = ±1.43, even though the minimum value is the same.[7]
Inmathematics, the arguments of the maxima (abbreviatedarg max or argmax) and arguments of the minima (abbreviated arg min or argmin) are the input points at which afunction output value ismaximized and minimized, respectively.[8] While thearguments are defined over thedomain of a function, the output is part of itscodomain.

See also

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Notes

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  1. ^PL:maxima andminima (ormaximums andminimums).
  2. ^PL:extrema.

References

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  1. ^Stewart, James (2008).Calculus: Early Transcendentals (6th ed.).Brooks/Cole.ISBN 978-0-495-01166-8.
  2. ^Larson, Ron; Edwards, Bruce H. (2009).Calculus (9th ed.).Brooks/Cole.ISBN 978-0-547-16702-2.
  3. ^Thomas, George B.; Weir, Maurice D.;Hass, Joel (2010).Thomas' Calculus: Early Transcendentals (12th ed.).Addison-Wesley.ISBN 978-0-321-58876-0.
  4. ^Weisstein, Eric W."Minimum".mathworld.wolfram.com. Retrieved2020-08-30.
  5. ^Weisstein, Eric W."Maximum".mathworld.wolfram.com. Retrieved2020-08-30.
  6. ^abGarrett, Paul."Minimization and maximization refresher".
  7. ^"The Unnormalized Sinc FunctionArchived 2017-02-15 at theWayback Machine", University of Sydney
  8. ^For clarity, we refer to the input (x) aspoints and the output (y) asvalues; comparecritical point andcritical value.

External links

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