Inmathematics, asequence (s1,s2,s3, ...) ofreal numbers is said to beequidistributed, oruniformly distributed, if the proportion of terms falling in a subinterval is proportional to the length of that subinterval. Such sequences are studied inDiophantine approximation theory and have applications toMonte Carlo integration.
A sequence (s1,s2,s3, ...) ofreal numbers is said to beequidistributed on a non-degenerateinterval [a,b] if for every subinterval [c,d ] of [a,b] we have
(Here, the notation |{s1,...,sn} ∩ [c,d ]| denotes the number of elements, out of the firstn elements of the sequence, that are betweenc andd.)
For example, if a sequence is equidistributed in [0, 2], since the interval [0.5, 0.9] occupies 1/5 of the length of the interval [0, 2], asn becomes large, the proportion of the firstn members of the sequence which fall between 0.5 and 0.9 must approach 1/5. Loosely speaking, one could say that each member of the sequence is equally likely to fall anywhere in its range. However, this is not to say that (sn) is a sequence ofrandom variables; rather, it is a determinate sequence of real numbers.
We define thediscrepancyDN for a sequence (s1,s2,s3, ...) with respect to the interval [a, b] as
A sequence is thus equidistributed if the discrepancyDN tends to zero asN tends to infinity.
Equidistribution is a rather weak criterion to express the fact that a sequence fills the segment leaving no gaps. For example, the drawings of a random variable uniform over a segment will be equidistributed in the segment, but there will be large gaps compared to a sequence which first enumerates multiples of ε in the segment, for some small ε, in an appropriately chosen way, and then continues to do this for smaller and smaller values of ε. For stronger criteria and for constructions of sequences that are more evenly distributed, seelow-discrepancy sequence.
Recall that iff is afunction having aRiemann integral in the interval [a,b], then its integral is the limit ofRiemann sums taken by sampling the functionf in aset of points chosen from a fine partition of the interval. Therefore, if some sequence is equidistributed in [a,b], it is expected that this sequence can be used to calculate the integral of a Riemann-integrable function. This leads to the following criterion[1] for an equidistributed sequence:
Suppose (s1,s2,s3, ...) is a sequence contained in the interval [a,b]. Then the following conditions are equivalent:
| Proof |
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| First note that the definition of an equidistributed sequence is equivalent to the integral criterion wheneverf is theindicator function of an interval: Iff =1[c,d], then the left hand side is the proportion of points of the sequence falling in the interval [c,d], and the right hand side is exactly This means 2 ⇒ 1 (since indicator functions are Riemann-integrable), and 1 ⇒ 2 forf being an indicator function of an interval. It remains to assume that the integral criterion holds for indicator functions and prove that it holds for general Riemann-integrable functions as well. Note that both sides of the integral criterion equation arelinear inf, and therefore the criterion holds forlinear combinations of interval indicators, that is,step functions. To show it holds forf being a general Riemann-integrable function, first assumef is real-valued. Then by usingDarboux's definition of the integral, we have for everyε > 0 two step functionsf1 andf2 such thatf1 ≤ f ≤ f2 and Notice that: By subtracting, we see that thelimit superior and limit inferior of differ by at most ε. Since ε is arbitrary, we have the existence of the limit, and by Darboux's definition of the integral, it is the correct limit. Finally, for complex-valued Riemann-integrable functions, the result follows again from linearity, and from the fact that every such function can be written asf = u +vi, whereu,v are real-valued and Riemann-integrable. ∎ |
This criterion leads to the idea ofMonte-Carlo integration, where integrals are computed by sampling the function over a sequence of random variables equidistributed in the interval.
It is not possible to generalize the integral criterion to a class of functions bigger than just the Riemann-integrable ones. For example, if theLebesgue integral is considered andf is taken to be inL1, then this criterion fails. As acounterexample, takef to be theindicator function of some equidistributed sequence. Then in the criterion, the left hand side is always 1, whereas the right hand side is zero, because the sequence iscountable, sof is zeroalmost everywhere.
In fact, thede Bruijn–Post Theorem states the converse of the above criterion: Iff is a function such that the criterion above holds for any equidistributed sequence in [a,b], thenf is Riemann-integrable in [a,b].[2]
A sequence (a1,a2,a3, ...) of real numbers is said to beequidistributed modulo 1 oruniformly distributed modulo 1 if the sequence of thefractional parts ofan, denoted by (an) or byan − ⌊an⌋, is equidistributed in the interval [0, 1].

This was proven by Weyl and is an application of van der Corput's difference theorem.[4]
Weyl's criterion states that the sequencean is equidistributed modulo 1if and only if for all non-zerointegers ℓ,
The criterion is named after, and was first formulated by,Hermann Weyl.[7] It allows equidistribution questions to be reduced to bounds onexponential sums, a fundamental and general method.
| Sketch of proof |
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| If the sequence is equidistributed modulo 1, then we can apply the Riemann integral criterion (described above) on the function which has integral zero on the interval [0, 1]. This gives Weyl's criterion immediately. Conversely, suppose Weyl's criterion holds. Then the Riemann integral criterion holds for functionsf as above, and by linearity of the criterion, it holds forf being anytrigonometric polynomial. By theStone–Weierstrass theorem and an approximation argument, this extends to anycontinuous functionf. Finally, letf be the indicator function of an interval. It is possible to boundf from above and below by two continuous functions on the interval, whose integrals differ by an arbitrary ε. By an argument similar to the proof of the Riemann integral criterion, it is possible to extend the result to anyinterval indicator functionf, thereby proving equidistribution modulo 1 of the given sequence. ∎ |
The sequencevn of vectors inRk is equidistributed modulo 1 if and only if for any non-zero vector ℓ ∈ Zk,
Weyl's criterion can be used to easily prove theequidistribution theorem, stating that the sequence of multiples 0,α, 2α, 3α, ... of some real numberα is equidistributed modulo 1 if and only ifα is irrational.[3]
Supposeα is irrational and denote our sequence byaj = jα (wherej starts from 0, to simplify the formula later). Letℓ ≠ 0 be an integer. Sinceα is irrational,ℓα can never be an integer, so can never be 1. Using the formula for the sum of a finitegeometric series,
a finite bound that does not depend onn. Therefore, after dividing byn and lettingn tend to infinity, the left hand side tends to zero, and Weyl's criterion is satisfied.
Conversely, notice that ifα isrational then this sequence is not equidistributed modulo 1, because there are only a finite number of options for the fractional part ofaj = jα.
A sequence of real numbers is said to bek-uniformly distributed mod 1 if not only the sequence of fractional parts is uniformly distributed in but also the sequence, where is defined as, is uniformly distributed in.
A sequence of real numbers is said to becompletely uniformly distributed mod 1 it is-uniformly distributed for each natural number.
For example, the sequence is uniformly distributed mod 1 (or 1-uniformly distributed) for any irrational number, but is never even 2-uniformly distributed. In contrast, the sequence is completely uniformly distributed for almost all (i.e., for all except for a set of measure 0).
A theorem ofJohannes van der Corput[8] states that if for eachh the sequencesn+h −sn is uniformly distributed modulo 1, then so issn.[9][10][11]
Avan der Corput set is a setH of integers such that if for eachh inH the sequencesn+h −sn is uniformly distributed modulo 1, then so is sn.[10][11]
Metric theorems describe the behaviour of a parametrised sequence foralmost all values of some parameterα: that is, for values ofα not lying in some exceptional set ofLebesgue measure zero.
It is not known whether the sequences (en ) or (π n ) are equidistributed mod 1. However it is known that the sequence (αn) isnot equidistributed mod 1 ifα is aPV number.
A sequence (s1,s2,s3, ...) of real numbers is said to bewell-distributed on [a,b] if for any subinterval [c,d ] of [a,b] we have
uniformly ink. Clearly every well-distributed sequence is uniformly distributed, but the converse does not hold. The definition of well-distributed modulo 1 is analogous.
For an arbitraryprobability measure space, a sequence of points is said to be equidistributed with respect to if the mean ofpoint measuresconverges weakly to:[13]
In anyBorelprobability measure on aseparable,metrizable space, there exists an equidistributed sequence with respect to the measure; indeed, this follows immediately from the fact that such a space isstandard.
The general phenomenon of equidistribution comes up a lot for dynamical systems associated withLie groups, for example in Margulis' solution to theOppenheim conjecture.