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Choice sequence

From Wikipedia, the free encyclopedia

Inintuitionistic mathematics, achoice sequence is aconstructive formulation of asequence. Since the Intuitionistic school of mathematics, as formulated byL. E. J. Brouwer, rejects the idea of acompleted infinity, in order to use a sequence (which is, in classical mathematics, an infinite object), we must have a formulation of a finite, constructible object that can serve the same purpose as a sequence. Thus, Brouwer formulated the choice sequence, which is given as a construction, rather than an abstract, infinite object.[1]

Lawlike and lawless sequences

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A distinction is made betweenlawless andlawlike sequences.[2] Alawlike sequence is one that can be described completely—it is a completed construction, that can be fully described. For example, thenatural numbersN{\displaystyle \mathbb {N} } can be thought of as a lawlike sequence: the sequence can be fully constructively described by the unique element 0 and asuccessor function. Given this formulation, we know that thei{\displaystyle i}th element in the sequence of natural numbers will be the numberi1{\displaystyle i-1}. Similarly, afunctionf:NN{\displaystyle f:\mathbb {N} \mapsto \mathbb {N} } mapping from the natural numbers into the natural numbers effectively determines the value for any argument it takes, and thus describes a lawlike sequence.

Alawless (also,free) sequence, on the other hand, is one that is not predetermined. It is to be thought of as a procedure for generating values for the arguments 0, 1, 2, .... That is, a lawless sequenceα{\displaystyle \alpha } is a procedure for generatingα0{\displaystyle \alpha _{0}},α1{\displaystyle \alpha _{1}}, ... (the elements of the sequenceα{\displaystyle \alpha }) such that:

Note that the first point above is slightly misleading, as we may specify, for example, that the values in a sequence be drawn exclusively from the set of natural numbers—we can specify,a priori, the range of the sequence.

The canonical example of a lawless sequence is the series of rolls of adie. We specify which die to use and, optionally, specify in advance the values of the firstk{\displaystyle k} rolls (forkN{\displaystyle k\in \mathbb {N} }). Further, we restrict the values of the sequence to be in the set{1,2,3,4,5,6}{\displaystyle \{1,2,3,4,5,6\}}. This specification comprises the procedure for generating the lawless sequence in question. At no point, then, is any particular future value of the sequence known.

Axiomatization

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There are twoaxioms in particular that we expect to hold of choice sequences as described above. Letαn{\displaystyle \alpha \in n} denote the relation "the sequenceα{\displaystyle \alpha } begins with the initial sequencen{\displaystyle n}" for choice sequenceα{\displaystyle \alpha } and finite segmentn{\displaystyle n} (more specifically,n{\displaystyle n} will probably be an integerencoding a finite initial sequence).

We expect the following, called theaxiom of open data, to hold of all lawless sequences:A(α)n[αnβn[A(β)]]{\displaystyle A(\alpha )\rightarrow \exists n[\alpha \in n\,\land \,\forall \beta \in n[A(\beta )]]}whereA{\displaystyle A} is aone-place predicate. The intuitive justification for this axiom is as follows: in intuitionistic mathematics, verification thatA{\displaystyle A} holds of the sequenceα{\displaystyle \alpha } is given as aprocedure; at any point of execution of this procedure, we will have examined only a finite initial segment of the sequence. Intuitively, then, this axiom states that since, at any point of verifying thatA{\displaystyle A} holds ofα{\displaystyle \alpha }, we will only have verified thatA{\displaystyle A} holds for a finite initial sequence ofα{\displaystyle \alpha }; thus, it must be the case thatA{\displaystyle A} also holds for any lawless sequenceβ{\displaystyle \beta } sharing this initial sequence. This is so because, at any point in the procedure of verifyingA(α){\displaystyle A(\alpha )}, for any suchβ{\displaystyle \beta } sharing the initial prefix ofα{\displaystyle \alpha } encoded byn{\displaystyle n} that we have already examined, if we run the identical procedure onβ{\displaystyle \beta }, we will get the same result. The axiom can be generalized for any predicate taking an arbitrary number of arguments.

Another axiom is required for lawless sequences. Theaxiom of density, given by:nα[αn]{\displaystyle \forall n\,\exists \alpha [\alpha \in n]}states that, for any finite prefix (encoded by)n{\displaystyle n}, there is some sequenceα{\displaystyle \alpha } beginning with that prefix. We require this axiom so as not to have any "holes" in the set of choice sequences. This axiom is the reason we require that arbitrarily long finite initial sequences of lawless choice sequences can be specified in advance; without this requirement, the axiom of density is not necessarily guaranteed.

See also

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Notes

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  1. ^Troelstra 1982.
  2. ^Linnebo & Shapiro 2020, p. 3.

References

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