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Choi's theorem on completely positive maps

From Wikipedia, the free encyclopedia
Classification of completely positive maps

Inmathematics,Choi's theorem on completely positive maps is a result that classifiescompletely positive maps between finite-dimensional (matrix)C*-algebras. The theorem is due toMan-Duen Choi. An infinite-dimensional algebraic generalization of Choi's theorem is known asBelavkin's "Radon–Nikodym" theorem for completely positive maps.

Statement

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Choi's theorem. LetΦ:Cn×nCm×m{\displaystyle \Phi :\mathbb {C} ^{n\times n}\to \mathbb {C} ^{m\times m}} be a linear map. The following are equivalent:

(i)Φ isn-positive (i.e.(idnΦ)(A)Cn×nCm×m{\displaystyle \left(\operatorname {id} _{n}\otimes \Phi \right)(A)\in \mathbb {C} ^{n\times n}\otimes \mathbb {C} ^{m\times m}} is positive wheneverACn×nCn×n{\displaystyle A\in \mathbb {C} ^{n\times n}\otimes \mathbb {C} ^{n\times n}} is positive).
(ii) The matrix with operator entries
CΦ=(idnΦ)(ijEijEij)=ijEijΦ(Eij)Cnm×nm{\displaystyle C_{\Phi }=\left(\operatorname {id} _{n}\otimes \Phi \right)\left(\sum _{ij}E_{ij}\otimes E_{ij}\right)=\sum _{ij}E_{ij}\otimes \Phi (E_{ij})\in \mathbb {C} ^{nm\times nm}}
is positive semi-definite (PSD), whereEijCn×n{\displaystyle E_{ij}\in \mathbb {C} ^{n\times n}} is the matrix with 1 in theij-th entry and 0s elsewhere. (The matrixCΦ is sometimes called theChoi matrix ofΦ.)
(iii)Φ is completely positive.

Proof

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(i) implies (ii)

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We observe that if

E=ijEijEij,{\displaystyle E=\sum _{ij}E_{ij}\otimes E_{ij},}

thenE=E* andE2=nE, soE=n−1EE* which is positive. ThereforeCΦ =(In ⊗ Φ)(E) is positive by then-positivity of Φ.

(iii) implies (i)

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This holds trivially.

(ii) implies (iii)

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This mainly involves chasing the different ways of looking atCnm×nm:

Cnm×nmCnm(Cnm)CnCm(CnCm)Cn(Cn)Cm(Cm)Cn×nCm×m.{\displaystyle \mathbb {C} ^{nm\times nm}\cong \mathbb {C} ^{nm}\otimes (\mathbb {C} ^{nm})^{*}\cong \mathbb {C} ^{n}\otimes \mathbb {C} ^{m}\otimes (\mathbb {C} ^{n}\otimes \mathbb {C} ^{m})^{*}\cong \mathbb {C} ^{n}\otimes (\mathbb {C} ^{n})^{*}\otimes \mathbb {C} ^{m}\otimes (\mathbb {C} ^{m})^{*}\cong \mathbb {C} ^{n\times n}\otimes \mathbb {C} ^{m\times m}.}

Let the eigenvector decomposition ofCΦ be

CΦ=i=1nmλivivi,{\displaystyle C_{\Phi }=\sum _{i=1}^{nm}\lambda _{i}v_{i}v_{i}^{*},}

where the vectorsvi{\displaystyle v_{i}} lie inCnm . By assumption, each eigenvalueλi{\displaystyle \lambda _{i}} is non-negative so we can absorb the eigenvalues in the eigenvectors and redefinevi{\displaystyle v_{i}} so that

CΦ=i=1nmvivi.{\displaystyle \;C_{\Phi }=\sum _{i=1}^{nm}v_{i}v_{i}^{*}.}

The vector spaceCnm can be viewed as the direct sumi=1nCm{\displaystyle \textstyle \oplus _{i=1}^{n}\mathbb {C} ^{m}} compatibly with the above identificationCnmCnCm{\displaystyle \textstyle \mathbb {C} ^{nm}\cong \mathbb {C} ^{n}\otimes \mathbb {C} ^{m}}and the standard basis ofCn.

IfPkCm ×nm is projection onto thek-th copy ofCm, thenPk*Cnm×m is the inclusion ofCm as thek-th summand of the direct sum and

Φ(Ekl)=PkCΦPl=i=1nmPkvi(Plvi).{\displaystyle \;\Phi (E_{kl})=P_{k}\cdot C_{\Phi }\cdot P_{l}^{*}=\sum _{i=1}^{nm}P_{k}v_{i}(P_{l}v_{i})^{*}.}

Now if the operatorsViCm×n are defined on thek-th standardbasis vectorek ofCn by

Viek=Pkvi,{\displaystyle \;V_{i}e_{k}=P_{k}v_{i},}

then

Φ(Ekl)=i=1nmPkvi(Plvi)=i=1nmViekelVi=i=1nmViEklVi.{\displaystyle \Phi (E_{kl})=\sum _{i=1}^{nm}P_{k}v_{i}(P_{l}v_{i})^{*}=\sum _{i=1}^{nm}V_{i}e_{k}e_{l}^{*}V_{i}^{*}=\sum _{i=1}^{nm}V_{i}E_{kl}V_{i}^{*}.}

Extending by linearity gives us

Φ(A)=i=1nmViAVi{\displaystyle \Phi (A)=\sum _{i=1}^{nm}V_{i}AV_{i}^{*}}

for anyACn×n. Any map of this form is manifestly completely positive: the mapAViAVi{\displaystyle A\to V_{i}AV_{i}^{*}} is completely positive, and the sum (acrossi{\displaystyle i}) of completely positive operators is again completely positive. ThusΦ{\displaystyle \Phi } is completely positive, the desired result.

The above is essentially Choi's original proof. Alternative proofs have also been known.

Consequences

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Kraus operators

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In the context ofquantum information theory, the operators {Vi} are called theKraus operators (afterKarl Kraus) of Φ. Notice, given a completely positive Φ, its Kraus operators need not be unique. For example, any "square root" factorization of the Choi matrixCΦ =BB gives a set of Kraus operators.

Let

B=[b1,,bnm],{\displaystyle B^{*}=[b_{1},\ldots ,b_{nm}],}

wherebi*'s are the row vectors ofB, then

CΦ=i=1nmbibi.{\displaystyle C_{\Phi }=\sum _{i=1}^{nm}b_{i}b_{i}^{*}.}

The corresponding Kraus operators can be obtained by exactly the same argument from the proof.

When the Kraus operators are obtained from the eigenvector decomposition of the Choi matrix, because the eigenvectors form an orthogonal set, the corresponding Kraus operators are also orthogonal in theHilbert–Schmidtinner product. This is not true in general for Kraus operators obtained from square root factorizations. (Positive semidefinite matrices do not generally have a unique square-root factorizations.)

If two sets of Kraus operators {Ai}1nm and {Bi}1nm represent the same completely positive map Φ, then there exists a unitaryoperator matrix

{Uij}ijCnm2×nm2such thatAi=j=1UijBj.{\displaystyle \{U_{ij}\}_{ij}\in \mathbb {C} ^{nm^{2}\times nm^{2}}\quad {\text{such that}}\quad A_{i}=\sum _{j=1}U_{ij}B_{j}.}

This can be viewed as a special case of the result relating twominimal Stinespring representations.

Alternatively, there is an isometryscalar matrix {uij}ijCnm ×nm such that

Ai=j=1uijBj.{\displaystyle A_{i}=\sum _{j=1}u_{ij}B_{j}.}

This follows from the fact that for two square matricesM andN,M M* =N N* if and only ifM = N U for some unitaryU.

Completely copositive maps

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It follows immediately from Choi's theorem that Φ is completely copositive if and only if it is of the form

Φ(A)=iViATVi.{\displaystyle \Phi (A)=\sum _{i}V_{i}A^{T}V_{i}^{*}.}

Hermitian-preserving maps

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Choi's technique can be used to obtain a similar result for a more general class of maps. Φ is said to be Hermitian-preserving ifA is Hermitian implies Φ(A) is also Hermitian. One can show Φ is Hermitian-preserving if and only if it is of the form

Φ(A)=i=1nmλiViAVi{\displaystyle \Phi (A)=\sum _{i=1}^{nm}\lambda _{i}V_{i}AV_{i}^{*}}

where λi are real numbers, the eigenvalues ofCΦ, and eachVi corresponds to an eigenvector ofCΦ. Unlike the completely positive case,CΦ may fail to be positive. Since Hermitian matrices do not admit factorizations of the formB*B in general, the Kraus representation is no longer possible for a given Φ.

See also

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References

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  • M.-D. Choi,Completely Positive Linear Maps on Complex Matrices, Linear Algebra and its Applications, 10, 285–290 (1975).
  • V. P. Belavkin, P. Staszewski,Radon-Nikodym Theorem for Completely Positive Maps, Reports on Mathematical Physics, v.24, No 1, 49–55 (1986).
  • J. de Pillis,Linear Transformations Which Preserve Hermitian and Positive Semidefinite Operators, Pacific Journal of Mathematics, 23, 129–137 (1967).
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