In the mathematical discipline ofcomplex analysis, theanalytic capacity of acompact subsetK of thecomplex plane is a number that denotes "how big" aboundedanalytic function onC \ K can become. Roughly speaking,γ(K) measures the size of theunit ball of the space of bounded analytic functions outsideK.
It was first introduced byLars Ahlfors in the 1940s while studying the removability ofsingularities of bounded analytic functions.
LetK ⊂C becompact. Then its analytic capacity is defined to be
Here, denotes the set ofbounded analyticfunctionsU →C, wheneverU is anopen subset of thecomplex plane. Further,
Note that, where. However, usually.
Equivalently, the analytic capacity may be defined as[1]
whereC is a contour enclosingK and the supremum is taken overf satisfying the same conditions as above:f is bounded analytic outsideK, the bound is one, and
IfA ⊂C is an arbitrary set, then we define
The compact setK is calledremovable if, whenever Ω is an open set containingK, every function which is bounded and holomorphic on the set Ω \ K has an analytic extension to all of Ω. ByRiemann's theorem for removable singularities, everysingleton is removable. This motivated Painlevé to pose a more general question in 1880: "Which subsets ofC are removable?"
It is easy to see thatK is removable if and only ifγ(K) = 0. However, analytic capacity is a purely complex-analytic concept, and much more work needs to be done in order to obtain a more geometric characterization.
For each compactK ⊂C, there exists a unique extremal function, i.e. such that,f(∞) = 0 andf′(∞) =γ(K). This function is called theAhlfors function ofK. Its existence can be proved by using a normal family argument involvingMontel's theorem.
Let dimH denoteHausdorff dimension andH1 denote 1-dimensionalHausdorff measure. ThenH1(K) = 0 impliesγ(K) = 0 while dimH(K) > 1 guaranteesγ(K) > 0. However, the case when dimH(K) = 1 andH1(K) ∈ (0, ∞] is more difficult.
Given the partial correspondence between the 1-dimensional Hausdorff measure of a compact subset ofC and its analytic capacity, it might be conjectured thatγ(K) = 0 impliesH1(K) = 0. However, this conjecture is false. A counterexample was first given byA. G. Vitushkin, and a much simpler one byJohn B. Garnett in his 1970 paper. This latter example is thelinear four corners Cantor set, constructed as follows:
LetK0 := [0, 1] × [0, 1] be the unit square. Then,K1 is the union of 4 squares of side length 1/4 and these squares are located in the corners ofK0. In general,Kn is the union of 4n squares (denoted by) of side length 4−n, each being in the corner of some. TakeK to be the intersection of allKn then butγ(K) = 0.
LetK ⊂C be a compact set. Vitushkin's conjecture states that
where denotes the orthogonal projection in direction θ. By the results described above, Vitushkin's conjecture is true when dimHK ≠ 1.
Guy David published a proof in 1998 of Vitushkin's conjecture for the case dimHK = 1 andH1(K) < ∞. In 2002,Xavier Tolsa proved that analytic capacity is countably semiadditive. That is, there exists an absolute constantC > 0 such that ifK ⊂C is a compact set and, where eachKi is a Borel set, then.
David's and Tolsa's theorems together imply that Vitushkin's conjecture is true whenK isH1-sigma-finite.
In the nonH1-sigma-finite case, Pertti Mattila proved in 1986[2] that the conjecture is false, but his proof did not specify which implication of the conjecture fails. Subsequent work by Jones and Muray[3] produced an example of a set with zero Favard length and positive analytic capacity, explicitly disproving one of the directions of the conjecture. As of 2023 it is not known whether the other implication holds but some progress has been made towards a positive answer by Chang and Tolsa.[4]