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Commutator subgroup

From Wikipedia, the free encyclopedia
(Redirected fromAbelianization)
Smallest normal subgroup by which the quotient is commutative

Inmathematics, more specifically inabstract algebra, thecommutator subgroup orderived subgroup of agroup is thesubgroupgenerated by all thecommutators of the group.[1][2]

The commutator subgroup is important because it is thesmallestnormal subgroup such that thequotient group of the original group by this subgroup isabelian. In other words,G/N{\displaystyle G/N} is abelianif and only ifN{\displaystyle N} contains the commutator subgroup ofG{\displaystyle G}. So in some sense it provides a measure of how far the group is from being abelian; the larger the commutator subgroup is, the "less abelian" the group is.

Commutators

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Main article:Commutator

For elementsg{\displaystyle g} andh{\displaystyle h} of a groupG, thecommutator ofg{\displaystyle g} andh{\displaystyle h} is[g,h]=g1h1gh{\displaystyle [g,h]=g^{-1}h^{-1}gh}. The commutator[g,h]{\displaystyle [g,h]} is equal to theidentity elemente if and only ifgh=hg{\displaystyle gh=hg} , that is, if and only ifg{\displaystyle g} andh{\displaystyle h} commute. In general,gh=hg[g,h]{\displaystyle gh=hg[g,h]}.

However, the notation is somewhat arbitrary and there is a non-equivalent variant definition for the commutator that has the inverses on the right hand side of the equation:[g,h]=ghg1h1{\displaystyle [g,h]=ghg^{-1}h^{-1}} in which caseghhg[g,h]{\displaystyle gh\neq hg[g,h]} but insteadgh=[g,h]hg{\displaystyle gh=[g,h]hg}.

An element ofG of the form[g,h]{\displaystyle [g,h]} for someg andh is called a commutator. The identity elemente = [e,e] is always a commutator, and it is the only commutator if and only ifG is abelian.

Here are some simple but useful commutator identities, true for any elementss,g,h of a groupG:

The first and second identities imply that theset of commutators inG is closed under inversion and conjugation. If in the third identity we takeH =G, we get that the set of commutators is stable under anyendomorphism ofG. This is in fact a generalization of the second identity, since we can takef to be the conjugationautomorphism onG,xxs{\displaystyle x\mapsto x^{s}}, to get the second identity.

However, the product of two or more commutators need not be a commutator. A generic example is [a,b][c,d] in thefree group ona,b,c,d. It is known that the least order of a finite group for which there exists two commutators whose product is not a commutator is 96; in fact there are two nonisomorphic groups of order 96 with this property.[3]

Definition

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This motivates the definition of thecommutator subgroup[G,G]{\displaystyle [G,G]} (also called thederived subgroup, and denotedG{\displaystyle G'} orG(1){\displaystyle G^{(1)}}) ofG: it is the subgroupgenerated by all the commutators.

It follows from this definition that any element of[G,G]{\displaystyle [G,G]} is of the form

[g1,h1][gn,hn]{\displaystyle [g_{1},h_{1}]\cdots [g_{n},h_{n}]}

for somenatural numbern{\displaystyle n}, where thegi andhi are elements ofG. Moreover, since([g1,h1][gn,hn])s=[g1s,h1s][gns,hns]{\displaystyle ([g_{1},h_{1}]\cdots [g_{n},h_{n}])^{s}=[g_{1}^{s},h_{1}^{s}]\cdots [g_{n}^{s},h_{n}^{s}]}, the commutator subgroup is normal inG. For any homomorphismf:GH,

f([g1,h1][gn,hn])=[f(g1),f(h1)][f(gn),f(hn)]{\displaystyle f([g_{1},h_{1}]\cdots [g_{n},h_{n}])=[f(g_{1}),f(h_{1})]\cdots [f(g_{n}),f(h_{n})]},

so thatf([G,G])[H,H]{\displaystyle f([G,G])\subseteq [H,H]}.

This shows that the commutator subgroup can be viewed as afunctor on thecategory of groups, some implications of which are explored below. Moreover, takingG =H it shows that the commutator subgroup is stable under every endomorphism ofG: that is, [G,G] is afully characteristic subgroup ofG, a property considerably stronger than normality.

The commutator subgroup can also be defined as the set of elementsg of the group that have an expression as a productg =g1g2 ...gk that can be rearranged to give the identity.

Derived series

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This construction can be iterated:

G(0):=G{\displaystyle G^{(0)}:=G}
G(n):=[G(n1),G(n1)]nN{\displaystyle G^{(n)}:=[G^{(n-1)},G^{(n-1)}]\quad n\in \mathbf {N} }

The groupsG(2),G(3),{\displaystyle G^{(2)},G^{(3)},\ldots } are called thesecond derived subgroup,third derived subgroup, and so forth, and the descendingnormal series

G(2)G(1)G(0)=G{\displaystyle \cdots \triangleleft G^{(2)}\triangleleft G^{(1)}\triangleleft G^{(0)}=G}

is called thederived series. This should not be confused with thelower central series, whose terms areGn:=[Gn1,G]{\displaystyle G_{n}:=[G_{n-1},G]}.

For a finite group, the derived series terminates in aperfect group, which may or may not be trivial. For an infinite group, the derived series need not terminate at a finite stage, and one can continue it to infiniteordinal numbers viatransfinite recursion, thereby obtaining thetransfinite derived series, which eventually terminates at theperfect core of the group.

Abelianization

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Given a groupG{\displaystyle G}, aquotient groupG/N{\displaystyle G/N} is abelian if and only if[G,G]N{\displaystyle [G,G]\subseteq N}.

The quotientG/[G,G]{\displaystyle G/[G,G]} is an abelian group called theabelianization ofG{\displaystyle G} orG{\displaystyle G}made abelian.[4] It is usually denoted byGab{\displaystyle G^{\operatorname {ab} }} orGab{\displaystyle G_{\operatorname {ab} }}.

There is a useful categorical interpretation of the mapφ:GGab{\displaystyle \varphi :G\rightarrow G^{\operatorname {ab} }}. Namelyφ{\displaystyle \varphi } is universal for homomorphisms fromG{\displaystyle G} to an abelian groupH{\displaystyle H}: for any abelian groupH{\displaystyle H} and homomorphism of groupsf:GH{\displaystyle f:G\to H} there exists a unique homomorphismF:GabH{\displaystyle F:G^{\operatorname {ab} }\to H} such thatf=Fφ{\displaystyle f=F\circ \varphi }. As usual for objects defined by universal mapping properties, this shows the uniqueness of the abelianizationGab{\displaystyle G^{\operatorname {ab} }} up to canonical isomorphism, whereas the explicit constructionGG/[G,G]{\displaystyle G\to G/[G,G]} shows existence.

The abelianization functor is theleft adjoint of the inclusion functor from thecategory of abelian groups to the category of groups. The existence of the abelianization functorGrpAb makes the categoryAb areflective subcategory of the category of groups, defined as a full subcategory whose inclusion functor has a left adjoint.

Another important interpretation ofGab{\displaystyle G^{\operatorname {ab} }} is asH1(G,Z){\displaystyle H_{1}(G,\mathbb {Z} )}, the firsthomology group ofG{\displaystyle G} with integral coefficients.

Classes of groups

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A groupG{\displaystyle G} is anabelian group if and only if the derived group is trivial: [G,G] = {e}. Equivalently, if and only if the group equals its abelianization. See above for the definition of a group's abelianization.

A groupG{\displaystyle G} is aperfect group if and only if the derived group equals the group itself: [G,G] =G. Equivalently, if and only if the abelianization of the group is trivial. This is "opposite" to abelian.

A group withG(n)={e}{\displaystyle G^{(n)}=\{e\}} for somen inN is called asolvable group; this is weaker than abelian, which is the casen = 1.

A group withG(n){e}{\displaystyle G^{(n)}\neq \{e\}} for alln inN is called anon-solvable group.

A group withG(α)={e}{\displaystyle G^{(\alpha )}=\{e\}} for someordinal number, possibly infinite, is called ahypoabelian group; this is weaker than solvable, which is the caseα is finite (a natural number).

Perfect group

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Main article:Perfect group

Whenever a groupG{\displaystyle G} has derived subgroup equal to itself,G(1)=G{\displaystyle G^{(1)}=G}, it is called aperfect group. This includes non-abeliansimple groups and thespecial linear groupsSLn(k){\displaystyle \operatorname {SL} _{n}(k)} for a fixed fieldk{\displaystyle k}.

Examples

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Map from Out

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Since the derived subgroup ischaracteristic, any automorphism ofG induces an automorphism of the abelianization. Since the abelianization is abelian,inner automorphisms act trivially, hence this yields a map

Out(G)Aut(Gab){\displaystyle \operatorname {Out} (G)\to \operatorname {Aut} (G^{\mbox{ab}})}

See also

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Notes

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  1. ^Dummit & Foote (2004)
  2. ^Lang (2002)
  3. ^Suárez-Alvarez
  4. ^Fraleigh (1976, p. 108)
  5. ^Suprunenko, D.A. (1976),Matrix groups, Translations of Mathematical Monographs, American Mathematical Society, Theorem II.9.4

References

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External links

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