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2019 Australian Open – Wheelchair women's singles

From Wikipedia, the free encyclopedia
Wheelchair women's singles
2019 Australian Open
Final
ChampionNetherlandsDiede de Groot
Runner-upJapanYui Kamiji
Score6–0, 6–2
Events
Singlesmenwomenboysgirls
Doublesmenwomenmixedboysgirls
WC Singlesmenwomenquad
WC Doublesmenwomenquad
Legendsmenwomenmixed
← 2018 ·Australian Open· 2020 →
2019 tennis event results
Main article:2019 Australian Open
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This article'slead sectionmay be too short to adequatelysummarize the key points. Please consider expanding the lead toprovide an accessible overview of all important aspects of the article.(July 2019)

Defending championDiede de Groot defeatedYui Kamiji in the final, 6–0, 6–2 to win the women's singles wheelchair tennis title at the 2019 Australian Open. It was her third step towards anon-calendar-year Grand Slam.

Seeds

[edit]
  1. NetherlandsDiede de Groot (champion)
  2. JapanYui Kamiji(final)

Draw

[edit]

Key

Draw

[edit]
First roundSemifinalsFinal
               
1NetherlandsDiede de Groot66
United KingdomLucy Shuker00
1NetherlandsDiede de Groot66
NetherlandsMarjolein Buis32
NetherlandsMarjolein Buis66
GermanySabine Ellerbrock14
1NetherlandsDiede de Groot66
2JapanYui Kamiji02
NetherlandsAniek van Koot67
South AfricaKgothatso Montjane15
NetherlandsAniek van Koot14
2JapanYui Kamiji66
Italy Giulia Capocci633
2JapanYui Kamiji776

References

[edit]
General
Specific
Australian Open wheelchair drawsheets
Men's
Singles
Doubles
Women's
Singles
Doubles
Quad
Singles
Doubles
Retrieved from "https://en.wikipedia.org/w/index.php?title=2019_Australian_Open_–_Wheelchair_women%27s_singles&oldid=1315503158"
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