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1899 Iowa gubernatorial election

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1899 Iowa gubernatorial election

← 1897November 7, 18991901 →
 
NomineeL. M. ShawFrederick Edward White
PartyRepublicanDemocratic
Popular vote239,464183,301
Percentage55.26%42.30%

County results
Shaw:     40-50%     50-60%     60-70%     70-80%
White:     40-50%     50-60%

Governor before election

L. M. Shaw
Republican

Elected Governor

L. M. Shaw
Republican

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The1899 Iowa gubernatorial election was held on November 7, 1899. IncumbentRepublicanL. M. Shaw defeatedDemocratic nomineeFrederick Edward White with 55.26% of the vote.

General election

[edit]

Candidates

[edit]

Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • Marshall W. Atwood, Prohibition
  • Charles Lloyd, People's
  • M. J. Kremer, Socialist Labor
  • C. C. Heacock, United Christian

Results

[edit]
1899 Iowa gubernatorial election[1]
PartyCandidateVotes%±%
RepublicanL. M. Shaw (incumbent)239,46455.26%
DemocraticFrederick Edward White183,30142.30%
ProhibitionMarshall W. Atwood7,6391.76%
PopulistCharles Lloyd1,6980.39%
Socialist LaborM. J. Kremer7570.18%
IndependentC. C. Heacock4840.11%
Majority56,163
Turnout
RepublicanholdSwing

References

[edit]
  1. ^Kalb, Deborah (December 24, 2015).Guide to U.S. Elections.ISBN 9781483380353. RetrievedAugust 7, 2020.
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