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1892 United States House of Representatives election in Wyoming

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1892 United States House of Representatives election in Wyoming

← 1890
November 8, 1892 (1892-11-08)
1894 →
 
NomineeHenry A. CoffeenClarence D. Clark
PartyDemocraticRepublican
Popular vote8,8558,394
Percentage51.34%48.66%

County results
Coffeen:     50–60%     60–70%
Clark:     50–60%
     No Data

U.S. Representative before election

Clarence D. Clark
Republican

Elected U.S. Representative

Henry A. Coffeen
Democratic

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TheWyoming United States House election for 1892 was held on November 3, 1892. Democratic Henry A. Coffeen defeated Republican incumbent Clarence D. Clark with 51.34% of the vote making Clark the first incumbent Representative from Wyoming to lose reelection.

Results

[edit]
United States House of Representatives election in Wyoming, 1892[1]
PartyCandidateVotes%
DemocraticHenry A. Coffeen8,85551.34%
RepublicanClarence D. Clark (inc.)8,39448.66%
Total votes17,249100%

References

[edit]
  1. ^"United States House of Representatives election in Wyoming, 1892".
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