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The1888 United States presidential election in Rhode Island took place on November 6, 1888, as part of the1888 United States presidential election. Voters chose four representatives, or electors to theElectoral College, who voted forpresident andvice president.
Rhode Island voted for theRepublican nominee,Benjamin Harrison, over theDemocratic nominee, incumbentPresidentGrover Cleveland. Harrison won the state by a margin of 10.89%.
| 1888 United States presidential election in Rhode Island[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Benjamin Harrison ofIndiana | Levi Parsons Morton ofNew York | 21,969 | 53.88% | 4 | 100.00% | ||
| Democratic | Grover Cleveland ofNew York (incumbent) | Allen Granberry Thurman ofOhio | 17,530 | 42.99% | 0 | 0.00% | ||
| Prohibition | Clinton Bowen Fisk ofNew Jersey | John Anderson Brooks ofMissouri | 1,251 | 3.07% | 0 | 0.00% | ||
| Union Labor | Alson Streeter ofIllinois | Charles E. Cunningham ofArkansas | 18 | 0.04% | 0 | 0.00% | ||
| N/A | Others | Others | 7 | 0.02% | 0 | 0.00% | ||
| Total | 40,775 | 100.00% | 4 | 100.00% | ||||
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