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The1884 United States presidential election in Delaware took place on November 4, 1884, as part of the1884 United States presidential election. Voters chose three representatives, or electors to theElectoral College, who voted forpresident andvice president.
Delaware voted for theDemocratic nominee,Grover Cleveland, over theRepublican nominee,James G. Blaine. Cleveland won the state by a margin of 13.35%.
| 1884 United States presidential election in Delaware[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland ofNew York | Thomas Andrews Hendricks ofIndiana | 16,957 | 56.55% | 3 | 100.00% | ||
| Republican | James Gillespie Blaine ofMaine | John Alexander Logan ofIllinois | 12,953 | 43.20% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John ofKansas | William Daniel ofMaryland | 64 | 0.21% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler ofMassachusetts | Absolom Madden West ofMississippi | 10 | 0.03% | 0 | 0.00% | ||
| Total | 29,984 | 100.00% | 3 | 100.00% | ||||
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