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1876 United States presidential election in Nebraska

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Main article:1876 United States presidential election
1876 United States presidential election in Nebraska

← 1872November 7, 18761880 →
 
NomineeRutherford B. HayesSamuel J. Tilden
PartyRepublicanDemocratic
Home stateOhioNew York
Running mateWilliam A. WheelerThomas A. Hendricks
Electoral vote30
Popular vote31,91517,413
Percentage64.70%35.30%

County Results

Hayes

  40–50%
  50–60%
  60–70%
  70–80%
  80–90%
  90–100%

Tilden

  40–50%
  50–60%
  60–70%
  70–80%


President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

Elections in Nebraska
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The1876 United States presidential election in Nebraska took place on November 7, 1876, as part of the1876 United States presidential election. Voters chose three representatives, or electors to theElectoral College, who voted forpresident andvice president.

Nebraska voted for theRepublican nominee,Ohio GovernorRutherford B. Hayes, over theDemocratic nominee,New York GovernorSamuel J. Tilden by a margin of 29.4%.

With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote afterVermont.[1]

Results

[edit]
1876 United States presidential election in Nebraska[2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
RepublicanRutherford B. Hayes ofOhioWilliam A. Wheeler ofNew York31,91564.70%3100.00%
DemocraticSamuel J. Tilden ofNew YorkThomas A. Hendricks ofIndiana17,41335.30%00.00%
Total49,328100.00%3100.00%

See also

[edit]

References

[edit]
  1. ^"1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. RetrievedMarch 5, 2018.
  2. ^"1876 Presidential General Election Results - Nebraska".
State and district results of the1876 United States presidential election
Electoral map, 1876 election
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