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The1872 United States presidential election in Vermont took place on November 5, 1872. All contemporary 37 states were part of the1872 United States presidential election. The state voters chose five electors to theElectoral College, which selected thepresident andvice president.
Vermont was won by theRepublican nominees, incumbentPresidentUlysses S. Grant ofIllinois and his running mateSenatorHenry Wilson ofMassachusetts. Grant and Wilson defeated theLiberal Republican andDemocratic nominees, formerCongressmanHorace Greeley ofNew York and his running mate formerSenator andGovernorBenjamin Gratz Brown ofMissouri by a margin of 57.67%.
With 78.29% of the popular vote, Vermont would be Grant's strongest victory in terms of percentage in the popular vote.[1] Grant's performance in the state was the third best for a Republican presidential candidate only afterWilliam McKinley's 80.08% in1896 and Grant's 78.57% fromfour years earlier.
| 1872 United States presidential election in Vermont[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Ulysses S. Grant ofIllinois | Henry Wilson ofMassachusetts | 41,480 | 78.29% | 5 | 100.00% | ||
| Liberal Republican | Horace Greeley ofNew York | Benjamin Gratz Brown ofMissouri | 10,926 | 20.62% | 0 | 0.00% | ||
| Bourbon Democrat | Charles O'Conor | John Quincy Adams II | 553 | 1.04% | 0 | 0.00% | ||
| N/A | Write ins | N/A | 21 | 0.04% | 0 | 0.00% | ||
| Total | 52,980 | 100.00% | 5 | 100.00% | ||||
State and district results of the1872 United States presidential election | ||
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