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 County results Burnside: 60–70% 70–80% 80–90% | |||||||||||||||||
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The1866 Rhode Island gubernatorial election was held on 4 April 1866 in order to elect thegovernor of Rhode Island.Republican nominee and formerUnion ArmyMajor GeneralAmbrose Burnside defeatedDemocratic nominee Lyman Pierce.[1]
On election day, 4 April 1866,Republican nomineeAmbrose Burnside won the election by a margin of 5,381 votes against his opponentDemocratic nominee Lyman Pierce, thereby retainingRepublican control over the office of governor. Burnside was sworn in as the 30thgovernor of Rhode Island on 1 May 1866.[2]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Ambrose Burnside | 8,197 | 73.36 | |
| Democratic | Lyman Pierce | 2,816 | 25.20 | |
| Scattering | 160 | 1.44 | ||
| Total votes | 11,221 | 100.00 | ||
| Republicanhold | ||||
