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Municipal results Buckingham: 50–60% 60–70% 70–80% Seymour: 50–60% 60–70% 70–80% Tie | |||||||||||||||||
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The1860 Connecticut gubernatorial election was held on April 2, 1860.[1][2] Incumbentgovernor andRepublican nomineeWilliam Alfred Buckingham defeated former governor andDemocratic nomineeThomas H. Seymour with 50.30% of the vote.
Major party candidates
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | William Alfred Buckingham (incumbent) | 44,458 | 50.30% | ||
| Democratic | Thomas H. Seymour | 43,920 | 49.70% | ||
| Majority | 538 | ||||
| Turnout | |||||
| Republicanhold | Swing | ||||
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