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Apresidential election was held inVermont on November 12, 1844 as part of the1844 United States presidential election.[1] Voters chose six representatives, or electors to theElectoral College, who voted forPresident andVice President.
Vermont voted for theWhig candidate,Henry Clay, overDemocratic candidateJames K. Polk andLiberty candidateJames G. Birney. Clay won Vermont by a margin of 17.88%.
With 54.84% of the popular vote, Vermont would prove to be Henry Clay's second strongest state afterRhode Island. Vermont would also prove to be James G. Birney's third strongest state afterNew Hampshire andMassachusetts.[2]
| 1844 United States presidential election in Vermont[3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay ofKentucky | Theodore Frelinghuysen ofNew York | 26,780 | 54.84% | 6 | 100.00% | ||
| Democratic | James K. Polk ofTennessee | George M. Dallas ofPennsylvania | 18,049 | 36.96% | 0 | 0.00% | ||
| Liberty | James G. Birney ofMichigan | Thomas Morris ofOhio | 3,970 | 8.13% | 0 | 0.00% | ||
| N/A | Others | Others | 30 | 0.06% | 0 | 0.00% | ||
| Total | 48,829 | 100.00% | 6 | 100.00% | ||||
State and district results of the1844 United States presidential election | ||
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