1840 United States presidential election in Kentucky

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Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 15 0 Popular vote 58,488 32,616 Percentage 64.20% 35.80%

County Results Harrison   50–60%   60–70%   70–80%   80–90%   90–100% Van Buren   50–60%   60–70%   70–80%   80–90%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

TheUnited States presidential election in Kentucky was held on November 2, 1840, as part of the1840 United States presidential election.^[1] Voters chose 15 representatives, or electors to theElectoral College, who voted forPresident andVice President.

Kentucky voted for theWhig candidate,William Henry Harrison, overDemocratic candidateMartin Van Buren. Harrison won Kentucky by a margin of 28.4%.

With 64.20% of the popular vote, Kentucky would prove to be Harrison's strongest state in the 1840 election.^[2]

• United States presidential elections in Kentucky

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