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Apresidential election was held inGeorgia on November 2, 1840 as part of the1840 United States presidential election.[1] Voters chose 11 representatives, or electors to theElectoral College, who voted forPresident andVice President.
Georgia voted for theWhig candidate,William Henry Harrison, overDemocratic candidateMartin Van Buren. Harrison won Georgia by a margin of 11.56%. This would be the last time that Georgia did not vote for the incumbent Democratic president until1964.
| United States presidential election in Georgia, 1840[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison ofOhio | John Tyler ofVirginia | 40,339 | 55.78% | 11 | 100.00% | ||
| Democratic | Martin Van Buren ofNew York | Richard M. Johnson ofKentucky | 31,983 | 44.22% | 0 | 0.00% | ||
| Total | 72,322 | 100.00% | 11 | 100.00% | ||||
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