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Apresidential election was held inArkansas on November 2, 1840 as part of the1840 United States presidential election.[1] Voters chose three representatives, or electors to theElectoral College, who voted forPresident andVice President.
Arkansas voted for theDemocratic candidate,Martin Van Buren, overWhig candidateWilliam Henry Harrison. Van Buren won Arkansas by a margin of 12.84%.
| 1840 United States presidential election in Arkansas[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren ofNew York | Richard Mentor Johnson ofKentucky | 6,679 | 56.42% | 3 | 100.00% | ||
| Whig | William Henry Harrison ofOhio | John Tyler ofVirginia | 5,160 | 43.58% | 0 | 0.00% | ||
| Total | 11,839 | 100.00% | 3 | 100.00% | ||||
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