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1832 United States presidential election in Missouri

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Main article:1832 United States presidential election
1832 United States presidential election in Missouri

← 1828
November 2 – December 5, 1832
1836 →
 
NomineeAndrew JacksonHenry Clay
PartyDemocraticNational Republican
Home stateTennesseeKentucky
Running mateMartin Van BurenJohn Sergeant
Electoral vote40
Popular vote8,9044,760
Percentage65.16%34.84%

County Results

Jackson

  40–50%
  70–80%
  80–90%
  90–100%

Clay

  50–60%
  60–70%

No Data/Vote

  

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The1832 United States presidential election in Missouri took place between November 2 and December 5, 1832, as part of the1832 United States presidential election. Voters chose four representatives, or electors to theElectoral College, who voted forPresident andVice President.

Missouri voted for theDemocratic Party candidate,Andrew Jackson, over theNational Republican candidate,Henry Clay. Jackson won Missouri by a margin of 30.33%. It is frequently reported that Jackson's popular vote win was unanimous, having received 5,159 or 5,192 votes. However, this was likely a reference to Jackson's plurality over Clay that was confounded with his total vote.[1]

Results

[edit]
1832 United States presidential election in Missouri[2]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)8,90465.16%4
National RepublicanHenry Clay4,76034.84%0
Totals13,664100.0%4

See also

[edit]

References

[edit]
  1. ^Dubin, Michael J.United States Presidential Elections. 1788–1870: The Official Results by County and State.ISBN 978-0-7864-6422-7.
  2. ^"Missouri Politics".Jeffersonian Republican. September 21, 1833. p. 2.
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