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1824 United States presidential election in Pennsylvania

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Main article:1824 United States presidential election
1824 United States presidential election in Pennsylvania

← 1820October 26 – December 2, 18241828 →
 
NomineeAndrew JacksonJohn Quincy AdamsWilliam H. Crawford
PartyDemocratic-RepublicanDemocratic-RepublicanDemocratic-Republican
Home stateTennesseeMassachusettsGeorgia
Running mateJohn C. CalhounJohn C. CalhounNathaniel Macon
Electoral vote2800
Popular vote35,9295,4364,182
Percentage76.04%11.50%8.85%

County Results
Jackson
  50–60%
  60–70%
  70–80%
  80–90%
  90–100%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

Elections in Pennsylvania
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The1824 United States presidential election in Pennsylvania took place between October 26 and December 2, 1824, as part of the1824 United States presidential election. Voters chose 28 representatives, or electors to theElectoral College, who voted forPresident andVice President.

During this election, theDemocratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency.Pennsylvania voted forAndrew Jackson overJohn Quincy Adams,William H. Crawford, andHenry Clay. Jackson won Pennsylvania by a wide margin of 64.54%.

This is the only time any presidential candidate has swept every Pennsylvania county.

Results

[edit]
1824 United States presidential election in Pennsylvania[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanAndrew Jackson35,92976.04%28
Democratic-RepublicanJohn Quincy Adams5,43611.50%0
Democratic-RepublicanWilliam H. Crawford4,1828.85%0
Democratic-RepublicanHenry Clay1,7053.61%0
Totals47,252100.0%28

See also

[edit]

References

[edit]
  1. ^"1824 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. RetrievedAugust 4, 2012.
State and district results of the1824 United States presidential election
Electoral map, 1824 election


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