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1824 United States presidential election in New Hampshire

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Main article:1824 United States presidential election
1824 United States presidential election in New Hampshire

← 1820
October 26 – December 2, 1824
1828 →
 
NomineeJohn Quincy AdamsWilliam H. Crawford
PartyDemocratic-RepublicanDemocratic-Republican
AllianceAdams-Clay RepublicanOld Republican
Home stateMassachusettsGeorgia
Running mateJohn C. CalhounNathaniel Macon
Electoral vote80
Popular vote9,389643
Percentage93.59%6.41%

County results
Adams
  90–100%


President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

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The1824 United States presidential election in New Hampshire took place between October 26 and December 2, 1824, as part of the1824 United States presidential election. Voters chose eight representatives, or electors, to theElectoral College, who voted forpresident andvice president.

During this election, theDemocratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency.New Hampshire voted forJohn Quincy Adams overWilliam H. Crawford,Andrew Jackson, andHenry Clay. Adams won New Hampshire by a margin of 87.18%.

Results

[edit]
1824 United States presidential election in New Hampshire[1]
PartyCandidateVotesPercentageElectoral votes
Democratic-RepublicanJohn Quincy Adams9,38993.59%8
Democratic-RepublicanWilliam H. Crawford6436.41%0
Totals10,032100.0%8

See also

[edit]

References

[edit]
  1. ^"1824 Presidential General Election Results - New Hampshire". U.S. Election Atlas. RetrievedFebruary 27, 2013.
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