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The1824 United States presidential election in Delaware took place between October 26 and December 2, 1824, as part of the1824 United States presidential election. Voters chose three representatives, or electors to theElectoral College, who voted forPresident andVice President.
During this election, theDemocratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency.Delaware cast two electoral votes forWilliam H. Crawford and one forJohn Quincy Adams.
| 1824 United States presidential election in Delaware[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | William H. Crawford | 2 | |||
| Democratic-Republican | John Quincy Adams | 1 | |||
| Democratic-Republican | Henry Clay | 0 | |||
| Democratic-Republican | Andrew Jackson | 0 | |||
| Totals | 3 | ||||