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Échenoz-le-Sec

Coordinates:47°32′28″N6°07′21″E / 47.5411°N 6.1225°E /47.5411; 6.1225
From Wikipedia, the free encyclopedia
Commune in Bourgogne-Franche-Comté, France
Échenoz-le-Sec
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Location of Échenoz-le-Sec
Échenoz-le-Sec is located in France
Échenoz-le-Sec
Échenoz-le-Sec
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Échenoz-le-Sec is located in Bourgogne-Franche-Comté
Échenoz-le-Sec
Échenoz-le-Sec
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Coordinates:47°32′28″N6°07′21″E / 47.5411°N 6.1225°E /47.5411; 6.1225
CountryFrance
RegionBourgogne-Franche-Comté
DepartmentHaute-Saône
ArrondissementVesoul
CantonRioz
Area
1
15.47 km2 (5.97 sq mi)
Population
 (2022)[1]
284
 • Density18.4/km2 (47.5/sq mi)
Time zoneUTC+01:00 (CET)
 • Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
70208 /70000
Elevation305–469 m (1,001–1,539 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Échenoz-le-Sec is acommune in theHaute-Saônedepartment in theregion ofBourgogne-Franche-Comté in easternFrance.The village of Échenoz-le-Sec belongs to the district of Vesoul and to the canton of Montbozon. The zip code of the village of Échenoz-le-Sec is 70000 and its code Insee(National Institute for Statistics and Economic Studies) is 70208.

See also

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References

[edit]
  1. ^"Populations de référence 2022" (in French). National Institute of Statistics and Economic Studies. 19 December 2024.
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Haute-SaôneCommunes of theHaute-Saône department
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