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Clairaut's relation (differential geometry)

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(Redirected fromClairaut's relation)
Formula in classical differential geometry
For other uses, seeClairaut's formula (disambiguation).

In classicaldifferential geometry,Clairaut's relation, named afterAlexis Claude de Clairaut, is a formula that characterizes the great circle paths on theunit sphere. The formula states that ifγ{\displaystyle \gamma } is a parametrization of a great circle then

ρ(γ(t))sinψ(γ(t))=constant,{\displaystyle \rho (\gamma (t))\sin \psi (\gamma (t))={\text{constant}},\,}

whereρ(P){\displaystyle \rho (P)} is the distance from a pointP{\displaystyle P} on thegreat circle to thez{\displaystyle z}-axis, andψ(P){\displaystyle \psi (P)} is the angle between the great circle and themeridian through the pointP{\displaystyle P}.

The relation remains valid for ageodesic on an arbitrarysurface of revolution.

A statement of the general version of Clairaut's relation is:[1]

Letγ{\displaystyle \gamma } be ageodesic on asurface of revolutionS{\displaystyle S}, letρ{\displaystyle \rho } be the distance of a point ofS{\displaystyle S} from theaxis of rotation, and letψ{\displaystyle \psi } be the angle betweenγ{\displaystyle \gamma } and themeridian ofS{\displaystyle S}. Thenρsinψ{\displaystyle \rho \sin \psi } is constant alongγ{\displaystyle \gamma }. Conversely, ifρsinψ{\displaystyle \rho \sin \psi } is constant along some curveγ{\displaystyle \gamma } in the surface, and if no part ofγ{\displaystyle \gamma } is part of some parallel ofS{\displaystyle S}, thenγ{\displaystyle \gamma } is a geodesic.

— Andrew Pressley:Elementary Differential Geometry, p. 183

Pressley (p. 185) explains this theorem as an expression ofconservation of angular momentum about theaxis of revolution when a particle moves along a geodesic under no forces other than those that keep it on the surface.

Now imagine a particle constrained to move on a surface of revolution, without external torque around the axis. By conservation of angular momentum:

rvθ=L,{\displaystyle r\,v_{\theta }=L,}

where

But geometrically,

vθ=|v|sinψ,{\displaystyle v_{\theta }=|v|\sin \psi ,}

If we normalize so the speed|v|=1{\displaystyle |v|=1} (unit speed geodesics), we get:

rsinψ=L|v|=constant.{\displaystyle r\sin \psi ={\frac {L}{|v|}}={\text{constant}}.}

References

[edit]
  • M. do Carmo,Differential Geometry of Curves and Surfaces, page 257.
  1. ^Andrew Pressley (2001).Elementary Differential Geometry. Springer. p. 183.ISBN 1-85233-152-6.


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