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2018 Brownlow Medal

From Wikipedia, the free encyclopedia

Award
2018 Brownlow Medal
2018 Brownlow Medalist,Tom Mitchell
Date24 September
LocationCrown Palladium
Hosted byBruce McAvaney
WinnerTom Mitchell (Hawthorn)
(28 votes)
Television/radio coverage
NetworkSeven Network
Telstra
← 2017 ·
· 2019 →

The2018 Brownlow Medal was the 91st year the award was presented to the player adjudged thefairest and best player during theAustralian Football League (AFL) home-and-away season.[1]Tom Mitchell of theHawthorn Football Club won the medal with 28 votes.

Leading vote-getters

[edit]
PlayerVotes
1stTom Mitchell (Hawthorn)28
2ndSteele Sidebottom (Collingwood)24
3rdAngus Brayshaw (Melbourne)21
=4thPatrick Cripps (Carlton)20
Max Gawn (Melbourne)
=6thRory Laird (Adelaide)19
Dustin Martin (Richmond)
=8thJack Steven (St Kilda)18
Dayne Beams (Brisbane Lions)
=10thBrodie Grundy (Collingwood)17
Patrick Dangerfield (Geelong)

Voting procedure

[edit]

The three fieldumpires (those umpires who control the flow of the game, as opposed to goal or boundary umpires) confer after each match and award three votes, two votes, and one vote to the players they regard as the best, second-best and third-best in the match, respectively. The votes are kept secret until the awards night, and they are read and tallied on the evening.[2]

References

[edit]
  1. ^Lovett, Michael (ed.).AFL Record Season Guide 2016.Docklands, Victoria: Slattery Media Group. p. 593.
  2. ^"Brownlow Medal history and winners - AFL.com.au".afl.com.au. Retrieved27 August 2018.
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