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1988 United States presidential election in Rhode Island

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Main article:1988 United States presidential election
1988 United States presidential election in Rhode Island

← 1984
November 8, 1988
1992 →
Turnout70.2%[1]Decrease 7.8pp
 
NomineeMichael DukakisGeorge H. W. Bush
PartyDemocraticRepublican
Home stateMassachusettsTexas
Running mateLloyd BentsenDan Quayle
Electoral vote40
Popular vote225,123177,761
Percentage55.64%43.93%

County Results
Municipality Results

Dukakis

  40–50%
  50–60%
  60–70%

Bush

  50–60%
  60–70%


President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

Elections in Rhode Island
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The1988 United States presidential election in Rhode Island took place on November 8, 1988, as part of the1988 United States presidential election, which was held throughout all 50 states andD.C. Voters chose four representatives, or electors to theElectoral College, who voted forpresident andvice president.

Rhode Island voted for theDemocratic nominee,Massachusetts GovernorMichael Dukakis, overRepublicanVice PresidentGeorge H. W. Bush. Dukakis took 55.64% of the vote to Bush's 43.93%, a margin of 11.71%. This made it one of 10 states (plus theDistrict of Columbia) to vote for Dukakis, while Bush won a convincing electoral victory nationwide.

AliberalNew England state, Rhode Island gave Dukakis his strongest state victory in the nation, with only the District of Columbia voting more Democratic. It was one of just two states (along withIowa) to vote Democratic by a double-digit margin, and one of only two states (along withHawaii) to have all of its counties go to Dukakis. Despite this, it was still a relatively strong Republican performance compared to how the state has trended since. The state has voted Democratic in every presidential election that followed. This is the last time until the2024 election that a Republican candidate won over 40% of the vote in Rhode Island.

To date, this is the last time that the towns ofBarrington,Charlestown,Little Compton,Middletown,North Kingstown, andPortsmouth voted Republican.

Results

[edit]
1988 United States presidential election in Rhode Island[2]
PartyCandidateVotesPercentageElectoral votes
DemocraticMichael Dukakis225,12355.64%4
RepublicanGeorge H. W. Bush177,76143.93%0
LibertarianRon Paul8250.20%0
New AllianceLenora Fulani2800.07%0
Peace and FreedomHerbert G. Lewin1950.05%0
America FirstDavid Duke1590.04%0
Socialist WorkersJames Warren1300.03%0
SocialistWilla Kenoyer960.02%0
Write-insWrite-ins510.01%0
Totals404,620100.00%4
Voter Turnout (Voting age/Registered)53%/74%

By county

[edit]
CountyMichael Dukakis
Democratic
George H.W. Bush
Republican
Various candidates
Other parties
MarginTotal votes cast
#%#%#%#%
Bristol11,16851.04%10,62648.56%890.40%5422.48%21,883
Kent37,22151.84%34,31447.79%2660.37%2,9074.05%71,801
Newport17,59750.76%16,92348.82%1440.42%6741.94%34,664
Providence135,92758.80%94,24840.77%9840.43%41,67918.03%231,159
Washington23,21051.51%21,65048.04%2020.45%1,5603.47%45,062
Totals225,12355.64%177,76143.93%1,7360.43%47,36211.71%404,620

Counties that flipped from Republican to Democratic

[edit]

See also

[edit]

References

[edit]
  1. ^This figure is calculated by dividing the total number of votes cast in 1988 (385,027) by an estimate of the number of registered voters in Rhode Island in 1988 (548,758). See"Voter Turnout, 1988". Rhode Island Board of Elections. RetrievedFebruary 6, 2018.
  2. ^"1988 Presidential General Election Results - Rhode Island". Dave Leip's Atlas of U.S. Presidential Elections. RetrievedFebruary 7, 2013.
State and district results of the1988 U.S. presidential election
Electoral map, 1988 election
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