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The1902 Minnesota Attorney General election was held on November 4, 1902, in order to elect theattorney general of Minnesota.Republican nominee andincumbent attorney generalWallace B. Douglas defeatedDemocratic nominee Frank D. Larrabee.[1]
On election day, November 4, 1902,Republican nomineeWallace B. Douglas won re-election by a margin of 75,224 votes against his opponentDemocratic nominee Frank D. Larrabee, thereby retaining Republican control over the office of attorney general. Douglas was sworn in for his third term on January 7, 1903.[2]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Wallace B. Douglas (incumbent) | 165,744 | 64.68 | |
| Democratic | Frank D. Larrabee | 90,520 | 35.32 | |
| Total votes | 256,264 | 100.00 | ||
| Republicanhold | ||||
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