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1860 Rhode Island gubernatorial election

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1860 Rhode Island gubernatorial election

← 1859
April 4, 1860
1861 →
 
NomineeWilliam Sprague IVSeth Padelford
PartyDemocraticRepublican
AllianceConservative
Popular vote12,27810,740
Percentage53.3%46.7%

County results
Sprague:     50–60%
Padelford:     50–60%

Governor before election

Thomas G. Turner
Republican

Elected Governor

William Sprague IV
Democratic

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Agubernatorial election was held inRhode Island on April 4, 1860. TheDemocratic andConservative candidateWilliam Sprague IV defeated theRepublican former member of theRhode Island House of Representatives fromProvidenceSeth Padelford.[1]

At the Republican state convention, Padelford, aRadical Republican, defeated the incumbentgovernorThomas G. Turner. Padelford's nomination precipitated a movement byConservative Republicans, formerWhigs, and Democrats to jointly nominate Sprague as the conservativefusion candidate. Sprague's surrogates portrayed the election as a choice between "Union and Disunion" and charged Padelford with representing "agitation, anarchy," and "black Republicanism."[2] The conservatives used several names during the campaign, including "Young Men's," "Conservative Republican," "Democratic," "Military," "Conservative Union," and "American."[3] Sprague's coalition subsequently became the foundation for the Rhode IslandConstitutional Union Party.[4]

Nominations

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Conservative Party

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A convention of the "conservative men of Rhode Island" met at Providence on February 1, 1860 and nominated Sprague for governor.[5] Sprague declined this nomination.[6] A second state convention was held on February 16, concurrently with the Democratic convention, where Sprague was again nominated unanimously.[7]

Candidate

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Democratic Party

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The Democratic state convention was held at Providence on February 16, 1860, concurrently with the Conservative Union convention. Sprague was nominated unanimously.[8]

Candidate

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Republican Party

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The Republican state convention met atProvidence on January 4, 1850. Padelford defeated Turner on the first ballot.[9]

Candidates

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Gubernatorial nomination

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Gubernatorial ballot[10]
Candidate1st
Seth Padelford55
Samuel G. Arnold34
Thomas G. Turner15

General election

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1860 Rhode Island gubernatorial election[1]
PartyCandidateVotes%
DemocraticWilliam Sprague IV12,27853.34
RepublicanSeth Padelford10,74046.66
Total votes23,018100.00
Democraticgain fromRepublican

Notes

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  1. ^abDubin 2003, p. 238.
  2. ^Smith 2017, pp. 140–41.
  3. ^DeSimone & Schofield 2015, Figs. 1-270, 1-271, 1-272, 1-273, 1-274, 1-275, 1-276, 1-277.
  4. ^Smith 2017, pp. 183–84.
  5. ^"The Rhode Island Republican Division".Vermont Phoenix. February 4, 1860.
  6. ^"Col. Sprague".Evening Star. February 8, 1860.
  7. ^"There are indications [...]".Alexandria Gazette. February 22, 1860.
  8. ^"There are indications [...]".Alexandria Gazette. February 22, 1860.
  9. ^"The Rhode Island Republican state convention [...]".The New York Herald. January 5, 1860.
  10. ^"The Republicans of Rhode Island".Bradford Reporter. January 12, 1860.

Bibliography

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