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 County Results Frémont 50–60% 60–70%
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The1856 United States presidential election in Rhode Island took place on November 4, 1856, as part of the1856 United States presidential election. Voters chose four representatives, or electors to theElectoral College, who voted forpresident andvice president.
Rhode Island voted for theRepublican candidate,John C. Frémont, over theDemocratic candidate,James Buchanan, and theKnow Nothing candidate,Millard Fillmore. Frémont won the state by a margin of 24.15%.
With 57.85% of the popular vote, Rhode Island proved to be Frémont's fourth strongest state in the 1856 election afterVermont,Massachusetts andMaine.[1]
| 1856 United States presidential election in Rhode Island[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | John C. Frémont ofCalifornia | William L. Dayton ofNew Jersey | 11,467 | 57.85% | 4 | 100.00% | ||
| Democratic | James Buchanan ofPennsylvania | John C. Breckinridge ofKentucky | 6,680 | 33.70% | 0 | 0.00% | ||
| Know Nothing | Millard Fillmore ofNew York | Andrew Jackson Donelson ofTennessee | 1,675 | 8.45% | 0 | 0.00% | ||
| Total | 19,822 | 100.00% | 4 | 100.00% | ||||
State results of the1856 U.S. presidential election | ||
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