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Apresidential election was held inIllinois on November 2, 1840 as part of the1840 United States presidential election.[1] Voters chose five representatives, or electors to theElectoral College, who voted forPresident andVice President.
Illinois voted for theDemocratic candidate,Martin Van Buren, overWhig candidateWilliam Henry Harrison. Van Buren won Illinois by a margin of 2.01%.
| 1840 United States presidential election in Illinois[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren ofNew York | Richard Mentor Johnson ofKentucky | 47,441 | 50.92% | 5 | 100.00% | ||
| Whig | William Henry Harrison ofOhio | John Tyler ofVirginia | 45,574 | 48.91% | 0 | 0.00% | ||
| Liberty | James G. Birney ofNew York | Thomas Earle ofPennsylvania | 160 | 0.17% | 0 | 0.00% | ||
| Total | 93,175 | 100.00% | 5 | 100.00% | ||||
State and district results of the1840 United States presidential election | ||
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