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The1812 United States presidential election in Rhode Island took place as part of the1812 United States presidential election. Voters chose four representatives, or electors, to theElectoral College, who voted forpresident andvice president.
Rhode Island voted for theDemocratic-Republican andFederalist supported candidate,DeWitt Clinton, over normal Democratic-Republican candidate, incumbent PresidentJames Madison. Clinton won Rhode Island by a margin of 65.93%. With Madison's second loss (the first one was1808), this marked the first time that a candidate or an incumbent president lost two presidential elections in Rhode Island.
| 1812 United States presidential election in Rhode Island[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican/Federalist | DeWitt Clinton | 4,032 | 65.93% | 4 | |
| Democratic-Republican | James Madison | 2,084 | 34.07% | – | |
| Totals | 6,116 | 100.00% | 4 | ||
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