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The1792 United States presidential election in Rhode Island took place as part of the1792 United States presidential election. Voters chose four representatives, or electors to theElectoral College who voted forPresident andVice President.
Rhode Island unanimously voted for the incumbentIndependent PresidentGeorge Washington.
| 1792 United States presidential election in Rhode Island[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Independent | George Washington(incumbent) | — | — | 4 | |
| Federalist | John Adams | — | — | 4 | |
| Totals | — | — | 8 | ||