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      std::remainder,std::remainderf,std::remainderl

      From cppreference.com
      <cpp‎ |numeric‎ |math
       
       
       
      Common mathematical functions
      Nearest integer floating point operations
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      (C++11)
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      Floating point manipulation functions
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      (C++11)
      (C++11)
      Classification and comparison
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      (C++11)
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      Types
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      Macro constants
       
      Defined in header<cmath>
      (1)
      float       remainder(float x,float y);

      double      remainder(double x,double y);

      longdouble remainder(longdouble x,longdouble y);
      (until C++23)
      constexpr/*floating-point-type*/

                  remainder(/*floating-point-type*/ x,

                             /*floating-point-type*/ y);
      (since C++23)
      float       remainderf(float x,float y);
      (2)(since C++11)
      (constexpr since C++23)
      longdouble remainderl(longdouble x,longdouble y);
      (3)(since C++11)
      (constexpr since C++23)
      SIMD overload(since C++26)
      Defined in header<simd>
      template<class V0,class V1>

      constexpr/*math-common-simd-t*/<V0, V1>

                  remainder(const V0& v_x,const V1& v_y);
      (S)(since C++26)
      Defined in header<cmath>
      template<class Integer>
      double      remainder( Integer x, Integer y);
      (A)(constexpr since C++23)
      1-3) Computes the IEEE remainder of the floating point division operationx/ y. The library provides overloads ofstd::remainder for all cv-unqualified floating-point types as the type of the parameters.(since C++23)
      S) The SIMD overload performs an element-wisestd::remainder onv_xandv_y.
      (Seemath-common-simd-t for its definition.)
      (since C++26)
      A) Additional overloads are provided for all integer types, which are treated asdouble.
      (since C++11)

      The IEEE floating-point remainder of the division operationx/ y calculated by this function is exactly the valuex- quo* y, where the valuequo is the integral value nearest the exact valuex/ y. When|quo - x / y| = ½, the valuequo is chosen to be even.

      In contrast tostd::fmod, the returned value is not guaranteed to have the same sign asx.

      If the returned value is zero, it will have the same sign asx.

      Contents

      [edit]Parameters

      x, y - floating-point or integer values

      [edit]Return value

      If successful, returns the IEEE floating-point remainder of the divisionx/ y as defined above.

      If a domain error occurs, an implementation-defined value is returned (NaN where supported).

      If a range error occurs due to underflow, the correct result is returned.

      Ify is zero, but the domain error does not occur, zero is returned.

      [edit]Error handling

      Errors are reported as specified inmath_errhandling.

      Domain error may occur ify is zero.

      If the implementation supports IEEE floating-point arithmetic (IEC 60559),

      • The currentrounding mode has no effect.
      • FE_INEXACT is never raised, the result is always exact.
      • Ifx is ±∞ andy is not NaN, NaN is returned andFE_INVALID is raised.
      • Ify is ±0 andx is not NaN, NaN is returned andFE_INVALID is raised.
      • If either argument is NaN, NaN is returned.

      [edit]Notes

      POSIX requires that a domain error occurs ifx is infinite ory is zero.

      std::fmod, but notstd::remainder is useful for doing silent wrapping of floating-point types to unsigned integer types:(0.0<=(y=std::fmod(std::rint(x),65536.0)))? y:65536.0+ y is in the range[-0.065535.0], which corresponds tounsignedshort, butstd::remainder(std::rint(x),65536.0) is in the range[-32767.0+32768.0], which is outside of the range ofsignedshort.

      The additional overloads are not required to be provided exactly as(A). They only need to be sufficient to ensure that for their first argumentnum1 and second argumentnum2:

      • Ifnum1 ornum2 has typelongdouble, thenstd::remainder(num1, num2) has the same effect asstd::remainder(static_cast<longdouble>(num1),
                       static_cast<longdouble>(num2))
        .
      • Otherwise, ifnum1 and/ornum2 has typedouble or an integer type, thenstd::remainder(num1, num2) has the same effect asstd::remainder(static_cast<double>(num1),
                       static_cast<double>(num2))
        .
      • Otherwise, ifnum1 ornum2 has typefloat, thenstd::remainder(num1, num2) has the same effect asstd::remainder(static_cast<float>(num1),
                       static_cast<float>(num2))
        .
      (until C++23)

      Ifnum1 andnum2 have arithmetic types, thenstd::remainder(num1, num2) has the same effect asstd::remainder(static_cast</*common-floating-point-type*/>(num1),
                     static_cast</*common-floating-point-type*/>(num2))
      , where/*common-floating-point-type*/ is the floating-point type with the greatestfloating-point conversion rank and greatestfloating-point conversion subrank between the types ofnum1 andnum2, arguments of integer type are considered to have the same floating-point conversion rank asdouble.

      If no such floating-point type with the greatest rank and subrank exists, thenoverload resolution does not result in a usable candidate from the overloads provided.

      (since C++23)

      [edit]Example

      Run this code
      #include <cfenv>#include <cmath>#include <iostream>// #pragma STDC FENV_ACCESS ON int main(){std::cout<<"remainder(+5.1, +3.0) = "<< std::remainder(5.1,3)<<'\n'<<"remainder(-5.1, +3.0) = "<< std::remainder(-5.1,3)<<'\n'<<"remainder(+5.1, -3.0) = "<< std::remainder(5.1,-3)<<'\n'<<"remainder(-5.1, -3.0) = "<< std::remainder(-5.1,-3)<<'\n'; // special valuesstd::cout<<"remainder(-0.0, 1.0) = "<< std::remainder(-0.0,1)<<'\n'<<"remainder(5.1, Inf) = "<< std::remainder(5.1,INFINITY)<<'\n'; // error handlingstd::feclearexcept(FE_ALL_EXCEPT);std::cout<<"remainder(+5.1, 0) = "<< std::remainder(5.1,0)<<'\n';if(fetestexcept(FE_INVALID))std::cout<<"    FE_INVALID raised\n";}

      Possible output:

      remainder(+5.1, +3.0) = -0.9remainder(-5.1, +3.0) = 0.9remainder(+5.1, -3.0) = -0.9remainder(-5.1, -3.0) = 0.9remainder(-0.0, 1.0) = -0remainder(5.1, Inf) = 5.1remainder(+5.1, 0) = -nan    FE_INVALID raised

      [edit]See also

      computes quotient and remainder of integer division
      (function)[edit]
      (C++11)(C++11)
      remainder of the floating point division operation
      (function)[edit]
      (C++11)(C++11)(C++11)
      signed remainder as well as the three last bits of the division operation
      (function)[edit]
      C documentation forremainder
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/numeric/math/remainder&oldid=180346"

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