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      std::is_assignable,std::is_trivially_assignable,std::is_nothrow_assignable

      From cppreference.com
      <cpp‎ |types
       
       
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      Compile-time rational arithmetic
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      Defined in header<type_traits>
      template<class T,class U>
      struct is_assignable;
      (1)(since C++11)
      template<class T,class U>
      struct is_trivially_assignable;
      (2)(since C++11)
      template<class T,class U>
      struct is_nothrow_assignable;
      (3)(since C++11)
      1) If the expressionstd::declval<T>()=std::declval<U>() is well-formed in unevaluated context, provides the member constantvalue equal totrue. Otherwise,value isfalse.Access checks are performed as if from a context unrelated to either type.
      2) Same as(1), but the evaluation of the assignment expression will not call any operation that is not trivial. For the purposes of this check, a call tostd::declval is considered trivial and not considered anodr-use ofstd::declval.
      3) Same as(1), but the evaluation of the assignment expression will not call any operation that is not noexcept.

      IfT orU is not a complete type, (possibly cv-qualified)void, or an array of unknown bound, the behavior is undefined.

      If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.

      If the program adds specializations for any of the templates described on this page, the behavior is undefined.

      Contents

      [edit]Helper variable templates

      template<class T,class U>
      constexprbool is_assignable_v= is_assignable<T, U>::value;
      (since C++17)
      template<class T,class U>
      constexprbool is_trivially_assignable_v= is_trivially_assignable<T, U>::value;
      (since C++17)
      template<class T,class U>
      constexprbool is_nothrow_assignable_v= is_nothrow_assignable<T, U>::value;
      (since C++17)
      [edit]

      Inherited fromstd::integral_constant

      Member constants

      value
      [static]
      true ifT is assignable fromU,false otherwise
      (public static member constant)

      Member functions

      operator bool
      converts the object tobool, returnsvalue
      (public member function)
      operator()
      (C++14)
      returnsvalue
      (public member function)

      Member types

      Type Definition
      value_typebool
      typestd::integral_constant<bool, value>

      [edit]Notes

      This trait does not check anything outside the immediate context of the assignment expression: if the use ofT orU would trigger template specializations, generation of implicitly-defined special member functions etc, and those have errors, the actual assignment may not compile even ifstd::is_assignable<T,U>::value compiles and evaluates totrue.

      [edit]Example

      Run this code
      #include <iostream>#include <string>#include <type_traits> struct Ex1{int n;}; int main(){std::cout<<std::boolalpha<<"int is assignable from int? "<< std::is_assignable<int,int>::value<<'\n'// 1 = 1; wouldn't compile<<"int& is assignable from int? "<< std::is_assignable<int&,int>::value<<'\n'// int a; a = 1; works<<"int is assignable from double? "<< std::is_assignable<int,double>::value<<'\n'<<"int& is nothrow assignable from double? "<< std::is_nothrow_assignable<int&,double>::value<<'\n'<<"string is assignable from double? "<< std::is_assignable<std::string,double>::value<<'\n'<<"Ex1& is trivially assignable from const Ex1&? "<< std::is_trivially_assignable<Ex1&,const Ex1&>::value<<'\n';}

      Output:

      int is assignable from int? falseint& is assignable from int? trueint is assignable from double? falseint& is nothrow assignable from double? truestring is assignable from double? trueEx1& is trivially assignable from const Ex1&? true

      [edit]See also

      checks if a type has a copy assignment operator
      (class template)[edit]
      checks if a type has a move assignment operator
      (class template)[edit]
      specifies that a type is assignable from another type
      (concept)[edit]
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/types/is_assignable&oldid=176480"

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