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      std::ratio_add

      From cppreference.com
      <cpp‎ |numeric‎ |ratio
       
       
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      Compile-time rational arithmetic
      Compile-time integer sequences
       
       
      Defined in header<ratio>
      template<class R1,class R2>
      using ratio_add=/* see below */;
      (since C++11)

      The alias templatestd::ratio_add denotes the result of adding two exact rational fractions represented by thestd::ratio specializationsR1 andR2.

      The result is astd::ratio specializationstd::ratio<U, V>, such that givenNum== R1::num* R2::den+ R2::num* R1::den andDenom== R1::den* R2::den (computed without arithmetic overflow),U isstd::ratio<Num, Denom>::num andV isstd::ratio<Num, Denom>::den.

      [edit]Notes

      IfU orV is not representable instd::intmax_t, the program is ill-formed. IfNum orDenom is not representable instd::intmax_t, the program is ill-formed unless the implementation yields correct values forU andV.

      The above definition requires that the result ofstd::ratio_add<R1, R2> be already reduced to lowest terms; for example,std::ratio_add<std::ratio<1,3>,std::ratio<1,6>> is the same type asstd::ratio<1,2>.

      [edit]Example

      Run this code
      #include <iostream>#include <ratio> int main(){using two_third=std::ratio<2,3>;using one_sixth=std::ratio<1,6>;using sum= std::ratio_add<two_third, one_sixth>; std::cout<<"2/3 + 1/6 = "<< sum::num<<'/'<< sum::den<<'\n';}

      Output:

      2/3 + 1/6 = 5/6

      [edit]See also

      subtracts tworatio objects at compile-time
      (alias template)[edit]
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/numeric/ratio/ratio_add&oldid=149447"

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