Thesededuction guides are provided forstack to allow deduction from underlying container type.

These overloads participate in overload resolution only if

• InputIt (if exists) satisfiesLegacyInputIterator,
• Container (if exists) does not satisfyAllocator,
• for(3)(until C++23)(4)(since C++23),Alloc satisfiesAllocator, and
• std::uses_allocator_v<Container, Alloc> istrue if bothContainer andAlloc exist.

Note: the extent to which the library determines that a type does not satisfyLegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfyAllocator is unspecified, except that as a minimum the member typeAlloc::value_type must exist and the expressionstd::declval<Alloc&>().allocate(std::size_t{}) must be well-formed when treated as an unevaluated operand.

[edit]Notes

[edit]Example

#include <stack>#include <vector> int main(){std::vector<int> v={1,2,3,4};std::stack s{v};// guide #1 deduces std::stack<int, vector<int>>}

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