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      log10, log10f, log10l

      From cppreference.com
      <c‎ |numeric‎ |math
       
       
       
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      log10
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      Defined in header<math.h>
      float       log10f(float arg);
      (1)(since C99)
      double      log10(double arg);
      (2)
      longdouble log10l(longdouble arg);
      (3)(since C99)
      Defined in header<tgmath.h>
      #define log10( arg )
      (4)(since C99)
      1-3) Computes the common (base-10) logarithm ofarg.
      4) Type-generic macro: Ifarg has typelongdouble,log10l is called. Otherwise, ifarg has integer type or the typedouble,log10 is called. Otherwise,log10f is called.

      Contents

      [edit]Parameters

      arg - floating-point value

      [edit]Return value

      If no errors occur, the common (base-10) logarithm ofarg (log10(arg) orlg(arg)) is returned.

      If a domain error occurs, an implementation-defined value is returned (NaN where supported).

      If a pole error occurs,-HUGE_VAL,-HUGE_VALF, or-HUGE_VALL is returned.

      [edit]Error handling

      Errors are reported as specified inmath_errhandling.

      Domain error occurs ifarg is less than zero.

      Pole error may occur ifarg is zero.

      If the implementation supports IEEE floating-point arithmetic (IEC 60559),

      • If the argument is ±0, -∞ is returned andFE_DIVBYZERO is raised.
      • If the argument is 1, +0 is returned
      • If the argument is negative, NaN is returned andFE_INVALID is raised.
      • If the argument is +∞, +∞ is returned
      • If the argument is NaN, NaN is returned.

      [edit]Example

      Run this code
      #include <errno.h>#include <fenv.h>#include <float.h>#include <math.h>#include <stdio.h>// #pragma STDC FENV_ACCESS ON int main(void){printf("log10(1000) = %f\n", log10(1000));printf("log10(0.001) = %f\n", log10(0.001));printf("base-5 logarithm of 125 = %f\n", log10(125)/ log10(5)); // special valuesprintf("log10(1) = %f\n", log10(1));printf("log10(+Inf) = %f\n", log10(INFINITY)); // error handlingerrno=0;feclearexcept(FE_ALL_EXCEPT);printf("log10(0) = %f\n", log10(0));if(errno==ERANGE)perror("    errno == ERANGE");if(fetestexcept(FE_DIVBYZERO))puts("    FE_DIVBYZERO raised");}

      Possible output:

      log10(1000) = 3.000000log10(0.001) = -3.000000base-5 logarithm of 125 = 3.000000log10(1) = 0.000000log10(+Inf) = inflog10(0) = -inf    errno == ERANGE: Numerical result out of range    FE_DIVBYZERO raised

      [edit]References

      • C23 standard (ISO/IEC 9899:2024):
      • 7.12.6.8 The log10 functions (p: TBD)
      • 7.25 Type-generic math <tgmath.h> (p: TBD)
      • F.10.3.8 The log10 functions (p: TBD)
      • C17 standard (ISO/IEC 9899:2018):
      • 7.12.6.8 The log10 functions (p: 179)
      • 7.25 Type-generic math <tgmath.h> (p: 272-273)
      • F.10.3.8 The log10 functions (p: 380)
      • C11 standard (ISO/IEC 9899:2011):
      • 7.12.6.8 The log10 functions (p: 245)
      • 7.25 Type-generic math <tgmath.h> (p: 373-375)
      • F.10.3.8 The log10 functions (p: 522)
      • C99 standard (ISO/IEC 9899:1999):
      • 7.12.6.8 The log10 functions (p: 225-226)
      • 7.22 Type-generic math <tgmath.h> (p: 335-337)
      • F.9.3.8 The log10 functions (p: 459)
      • C89/C90 standard (ISO/IEC 9899:1990):
      • 4.5.4.5 The log10 function

      [edit]See also

      (C99)(C99)
      computes natural (base-e) logarithm (\({\small \ln{x} }\)ln(x))
      (function)[edit]
      (C99)(C99)(C99)
      computes base-2 logarithm (\({\small \log_{2}{x} }\)log2(x))
      (function)[edit]
      (C99)(C99)(C99)
      computes natural (base-e) logarithm of 1 plus the given number (\({\small \ln{(1+x)} }\)ln(1+x))
      (function)[edit]
      Retrieved from "https://en.cppreference.com/mwiki/index.php?title=c/numeric/math/log10&oldid=172043"

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