numpy.char.count#

char.count(a,sub,start=0,end=None)[source]#

Returns an array with the number of non-overlapping occurrences ofsubstringsub in the range [start,end).

Parameters:

aarray-like, withStringDType,bytes_, orstr_ dtype

subarray-like, withStringDType,bytes_, orstr_ dtype

The substring to search for.

start, endarray_like, with any integer dtype

The range to look in, interpreted as in slice notation.

Returns:

yndarray

Output array of ints

See also

str.count

Examples

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>>>importnumpyasnp>>>c=np.array(['aAaAaA','  aA  ','abBABba'])>>>carray(['aAaAaA', '  aA  ', 'abBABba'], dtype='<U7')>>>np.strings.count(c,'A')array([3, 1, 1])>>>np.strings.count(c,'aA')array([3, 1, 0])>>>np.strings.count(c,'A',start=1,end=4)array([2, 1, 1])>>>np.strings.count(c,'A',start=1,end=3)array([1, 0, 0])

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