| Title: | Crossword, Scrabble and Anagram Solver |
| Version: | 0.1.0 |
| Date: | 2016-07-02 |
| Description: | Provides a large English words list and tools to find words by patterns. In particular, anagram finder and scrabble word finder. |
| URL: | https://github.com/idmn/wfindr |
| BugReports: | https://github.com/idmn/wfindr/issues |
| License: | GPL-2 |
| LazyData: | true |
| Depends: | R (≥ 3.1.2) |
| Imports: | dplyr, magrittr |
| RoxygenNote: | 5.0.1 |
| NeedsCompilation: | no |
| Packaged: | 2016-07-03 10:24:44 UTC; Jaroslav |
| Author: | Iaroslav Domin [aut, cre] |
| Maintainer: | Iaroslav Domin <ya.domin@gmail.com> |
| Repository: | CRAN |
| Date/Publication: | 2016-07-03 17:58:53 |
Characters count
Description
Calculates character frequencies in a vector.
Usage
char_count(x)Arguments
x | character vector, or a list that can be unlisted to a charactervector. |
Value
data.frame with two columns:char - character andcount- number of it's occurencies.
Examples
char_count("character")char_count(words.eng)Find words that fit the chosen parameters.
Description
Uses regex constructed bymodel_to_regex to searchwords. By default the search is done amongwords.eng.find_word returns a vector of found words,find_word_lreturns a logical vector that can be used for subsetting.
Usage
find_word(model = "*", allow = letters, ban = character(0), type = "usual", words = wfindr::words.eng)find_word_l(model = "*", allow = letters, ban = character(0), type = "usual", words = wfindr::words.eng)Arguments
model | pattern that a word should match. Consists of letters andunknown characters specifications. Dot |
allow | characters allowed to fill gaps in a word. Can be listed in asingle string or in a vector. By default is set to |
ban | characters not allowed to fill gaps in a word. |
type | can be
|
words | vector of words to search within. By default is set to |
See Also
Examples
## Search 4-letter words starting with "c".find_word("c.{3}")## Disallow "a" and "b".find_word("c.{3}", ban = "ab")## Allow only "a" and "b" to fill the gap.find_word("c.{3}", allow = "ab")## Allow "a", "b", and "c", but then ban "c"## result is the same as in the previous examplefind_word("c.{3}", allow = "abc", ban = "c")## Find no more than 4-letter words that have "th" bigramlibrary(magrittr)find_word(".{0,4}") %>% find_word("*th*", words = .)## count words that start with "th"sum(find_word_l("th*"))length(find_word("th*"))## Find words that can be constructed of the "thing" word's letters.find_word(allow = "thing", type = "scrabble")## Get at lest 4-letter words.find_word(".{4,}", allow = "thing", type = "scrabble")## Find anagrams of the word "thing"find_word(allow = "thing", type = "anagram")Build a regular expression to fit chosen parameters
Description
Build a regular expression to fit chosen parameters
Usage
model_to_regex(model = "*", allow = letters, ban = character(0), type = "usual")Arguments
model | pattern that a word should match. Consists of letters andunknown characters specifications. Dot |
allow | characters allowed to fill gaps in a word. Can be listed in asingle string or in a vector. By default is set to |
ban | characters not allowed to fill gaps in a word. |
type | can be
|
Warning
Iftype = "scrabble" or"anagram", outputregex will contain perl-like syntax. So, to use it ingrep orgsub for example, setperl parameter toTRUE.
See Also
Examples
## Regular expression to match all the 5-letter words starting with "c".model_to_regex("c.{4}")## Disallow "a" and "b".model_to_regex("c.{4}", ban = "ab")## Allow only "a" and "b" to fill the gap.model_to_regex("c.{4}", allow = "ab")## Allow "a", "b", and "c", but then ban "c" (result is the same as the previous example)model_to_regex("c.{4}", allow = "abc", ban = "c")## Regex to match all words that start with "p" and end with "zed".model_to_regex("p*zed")## Regex to match all the words that can be constructed of the word "thing".model_to_regex(allow = "thing", type = "scrabble")## Get at lest 4-letter words.model_to_regex(".{4,}", allow = "thing", type = "scrabble")## Regex to match anagrams of the word "thing"model_to_regex(allow = "thing", type = "anagram")Find words that can be constructed from the specified letters
Description
scrabble finds words that can be constructed from thespecified set of letters.anagram finds words that arepermutations of the specified set of letters. Usually this set of lettersis a word itself.
Usage
scrabble(allow, model = "*", ban = character(0), words = wfindr::words.eng)anagram(allow, model = "*", ban = character(0), words = wfindr::words.eng)Arguments
allow | characters allowed to use to construct words. |
model | pattern that a word should match. Consists of letters andunknown characters specifications. Dot |
ban | characters not allowed to fill gaps in a word. |
words | vector of words to search within. By default is set to |
Details
scrabble andanagram are functions built on top of thefind_word function with parametertype set to"scrabble" or"anagram" respectively andallowparameter moved to the first place to simplify usage (see the firstexample).
See Also
Examples
## Find all words that can be constructed of the "thing" word's lettersscrabble("thing")## same asfind_word(allow = "thing", type = "s")## take at least 4-letter wordsscrabble("thing", ".{4,}")## same asfind_word(".{4,}", "thing", type = "s")## Pick 8 random letters and find words that can be constructed of them.library(magrittr)sample(letters, 8, TRUE) %>% list(letters = ., words = scrabble(.))## Find anagrams of the word "thing"anagram("thing")English words list
Description
263,533 english words list took fromhttp://norvig.com/ngrams/(Seeword.list file).
Format
An object of classcharacter of length 263533.